A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants. Plant 1 Atlanta Plant 2 Plant 3 Dallas Seattle 84 70 59 76 76 64 82 74 62 77 74 70 71 70 76 84 86 59 Sample 79 75 65 mean Sample variance 27.2 34.8 45.6 Sample standard 5.22 5.90 6.75 deviation Set up the ANOVA table for these data. (Round your values for MSE and Fto two decimal places, and your p-value to four decimal places.) Source of Variation Degrees of Freedom Sum Mean of Squares Square F Pvalue Treatments 2 Enter an exact number Error Total Test for any significant difference in the mean examination score for the three plants. Use a- 0.05. State the null and alternative hypotheses. Ho: P1 2 3 Hai 1 2* 3 Ho: 2 3 Ha: Not all the population means are equal. Ho: At least two of the population means are equal. Hai At least two of the population means are different. Ho: 1 F2* F3 Hai 1"23 Ho: Not all the population means are equal. Find the value of the test statistic. (Round your answer to two decimal places.) 1.60 Find the p-value. (Round your answer to four decimal places.)

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A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality
awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score
is the same for all three plants.
Plant 1
Plant 2
Plant 3
Seattle
Atlanta
Dallas
84
70
59
76
76
64
82
74
62
77
74
70
71
70
76
84
86
59
Sample
79
75
65
mean
Sample
variance
27.2
34.8
45.6
Sample
standard
5.22
5.90
6.75
deviation
Set up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)
Source
Sum
Degrees
of Freedom
Mean
p-value
of Variation
of Squares
Square
Treatments
2
Enter an exact number.
Error
Total
Test for any significant difference in the mean examination score for the three plants. Use a = 0.05.
State the null and alternative hypotheses.
Ho: H1 = 42 = H3
Ha: #1 * H2 + H3
o Ho: H1 = H2 = 43
Ha: Not all the population means are equal.
Ho: At least two of the population means are equal.
Ha: At least two of the population means are different.
Ho: 41 + 42 + 43
Ha: H1 = #2 = #3
Ho: Not all the population means are equal.
Hai H1 = #2 = H3
Find the value of the test statistic. (Round your answer to two decimal places.)
1.60
Find the p-value. (Round your answer to four decimal places.)
p-value = .0027
Transcribed Image Text:A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants. Plant 1 Plant 2 Plant 3 Seattle Atlanta Dallas 84 70 59 76 76 64 82 74 62 77 74 70 71 70 76 84 86 59 Sample 79 75 65 mean Sample variance 27.2 34.8 45.6 Sample standard 5.22 5.90 6.75 deviation Set up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.) Source Sum Degrees of Freedom Mean p-value of Variation of Squares Square Treatments 2 Enter an exact number. Error Total Test for any significant difference in the mean examination score for the three plants. Use a = 0.05. State the null and alternative hypotheses. Ho: H1 = 42 = H3 Ha: #1 * H2 + H3 o Ho: H1 = H2 = 43 Ha: Not all the population means are equal. Ho: At least two of the population means are equal. Ha: At least two of the population means are different. Ho: 41 + 42 + 43 Ha: H1 = #2 = #3 Ho: Not all the population means are equal. Hai H1 = #2 = H3 Find the value of the test statistic. (Round your answer to two decimal places.) 1.60 Find the p-value. (Round your answer to four decimal places.) p-value = .0027
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