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A company has seven applicants for two positions: three women and four men. Suppose that the seven applicants are equally qualified and that no preference is given for choosing either gender. Let x equal the number of women chosen to fill the two positions. (a) Write the formula for p(x), the probability distribution of x. CAC, 3 p(x)=. 2- for x = 0, 1, 2 C₁₂ p(x)= c³c₂4 p(x) for x = 0, 1, 2, 3, 4, 5, 6, 7 = 2-x c/ c^c. 3 x2-x for x = 0, 1, 2, 3, 4, 5, 6, 7 C² c²c₂ p(x)=x2-x for x = 0, 1, 2 C²₂ c²c₂ª p(x) = x2-x for x = 0, 1, 2 (b) What are the mean and variance of this distribution? (Round your mean to one decimal place and your variance to two decimal places.) mean variance =

A company has seven applicants for two positions: three women and four men. Suppose that the seven applicants are equally qualified and that no preference is given for choosing either gender. Let x equal the number of women chosen to fill the two positions. (a) Write the formula for p(x), the probability distribution of x. CAC, 3 p(x)=. 2- for x = 0, 1, 2 C₁₂ p(x)= c³c₂4 p(x) for x = 0, 1, 2, 3, 4, 5, 6, 7 = 2-x c/ c^c. 3 x2-x for x = 0, 1, 2, 3, 4, 5, 6, 7 C² c²c₂ p(x)=x2-x for x = 0, 1, 2 C²₂ c²c₂ª p(x) = x2-x for x = 0, 1, 2 (b) What are the mean and variance of this distribution? (Round your mean to one decimal place and your variance to two decimal places.) mean variance =

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A company has seven applicants for two positions: three women and four men. Suppose that the seven applicants are equally qualified and that no preference is given for choosing either gender. Let \( x \) equal the number of women chosen to fill the two positions. (a) Write the formula for \( p(x) \), the probability distribution of \( x \). - \(\displaystyle p(x) = \frac{C_3^x \, C_4^{2-x}}{C_7^2} \quad \text{for } x = 0, 1, 2 \) - \(\displaystyle p(x) = \frac{C_3^x \, C_4^{2-x}}{C_7^2} \quad \text{for } x = 0, 1, 2, 3, 4, 5, 6, 7 \) - \(\displaystyle p(x) = \frac{C_4^x \, C_3^{2-x}}{C_7^2} \quad \text{for } x = 0, 1, 2, 3, 4, 5, 6, 7 \) - \(\displaystyle p(x) = \frac{C_7^2 \, C_4^{2-x}}{C_3^2} \quad \text{for } x = 0, 1, 2 \) - **\(\displaystyle p(x) = \frac{C_3^x \, C_4^{2-x}}{C_7^2} \quad \text{for } x = 0, 1, 2 \)** (b) What are the mean and variance of this distribution? (Round your mean to one decimal place and your variance to two decimal places.) - Mean = \(\, \boxed{\phantom{0}}\) - Variance = \(\, \boxed{\phantom{0}}\)
Transcribed Image Text:A company has seven applicants for two positions: three women and four men. Suppose that the seven applicants are equally qualified and that no preference is given for choosing either gender. Let \( x \) equal the number of women chosen to fill the two positions. (a) Write the formula for \( p(x) \), the probability distribution of \( x \). - \(\displaystyle p(x) = \frac{C_3^x \, C_4^{2-x}}{C_7^2} \quad \text{for } x = 0, 1, 2 \) - \(\displaystyle p(x) = \frac{C_3^x \, C_4^{2-x}}{C_7^2} \quad \text{for } x = 0, 1, 2, 3, 4, 5, 6, 7 \) - \(\displaystyle p(x) = \frac{C_4^x \, C_3^{2-x}}{C_7^2} \quad \text{for } x = 0, 1, 2, 3, 4, 5, 6, 7 \) - \(\displaystyle p(x) = \frac{C_7^2 \, C_4^{2-x}}{C_3^2} \quad \text{for } x = 0, 1, 2 \) - **\(\displaystyle p(x) = \frac{C_3^x \, C_4^{2-x}}{C_7^2} \quad \text{for } x = 0, 1, 2 \)** (b) What are the mean and variance of this distribution? (Round your mean to one decimal place and your variance to two decimal places.) - Mean = \(\, \boxed{\phantom{0}}\) - Variance = \(\, \boxed{\phantom{0}}\)
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