(d) Could p(y) for y = 1, ..., 6 be the pmf of Y? 92 --Select-- , because p(y) : y = 1

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I need part d) ONLY

A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the nature of the project) in applying for
a building permit. Let Y = the number of forms required of the next applicant. The probability that y forms are required is known to be proportional to y-that is,
p(y) = ky for y = 1, ..., 6. (Enter your answers as fractions.)
%3D
6
(a) What is the value of k? [Hint: p(y) = 1]
y = 1
k =
(b) What is the probability that at most four forms are required?
(c) What is the probability that between three and five forms (inclusive) are required?
y2
for y = 1, .
92
(d) Could p(y)
6 be the pmf of Y?
%3D
.../
6.
---Select--- O
because p(y)
y = 1
Transcribed Image Text:A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the nature of the project) in applying for a building permit. Let Y = the number of forms required of the next applicant. The probability that y forms are required is known to be proportional to y-that is, p(y) = ky for y = 1, ..., 6. (Enter your answers as fractions.) %3D 6 (a) What is the value of k? [Hint: p(y) = 1] y = 1 k = (b) What is the probability that at most four forms are required? (c) What is the probability that between three and five forms (inclusive) are required? y2 for y = 1, . 92 (d) Could p(y) 6 be the pmf of Y? %3D .../ 6. ---Select--- O because p(y) y = 1
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