For a large population of people, the probability distribution for the random variable X = the number of meals a person ate yesterday and the assigned probabilities is given below: Meals, X Probability (a) Find P(X= 5), the probability that a randomly selected person ate 5 meals yesterday. P(X= 5) = 1 2 3 4 5 0.17 0.35 0.24 0.17 ? (b) Find P(X ≤ 2), the probability that a randomly selected person ate 2 or fewer meals yesterday. P(X ≤ 2) = (c) Find the probability that a randomly selected person ate 1 meal or ate 5 meals yesterday. P = (d) Find P(X> 1), the probability that a randomly selected person ate more than 1 meal yesterday. P(X > 1) =
For a large population of people, the probability distribution for the random variable X = the number of meals a person ate yesterday and the assigned probabilities is given below: Meals, X Probability (a) Find P(X= 5), the probability that a randomly selected person ate 5 meals yesterday. P(X= 5) = 1 2 3 4 5 0.17 0.35 0.24 0.17 ? (b) Find P(X ≤ 2), the probability that a randomly selected person ate 2 or fewer meals yesterday. P(X ≤ 2) = (c) Find the probability that a randomly selected person ate 1 meal or ate 5 meals yesterday. P = (d) Find P(X> 1), the probability that a randomly selected person ate more than 1 meal yesterday. P(X > 1) =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![For a large population of people, the probability distribution for the random variable \( X \) (the number of meals a person ate yesterday) and the assigned probabilities is given below:
| Meals, \( X \) | 1 | 2 | 3 | 4 | 5 |
|-------------------|-----|-----|-----|-----|-----|
| Probability | 0.17| 0.35| 0.24| 0.17| ? |
### Questions
(a) Find \( P(X = 5) \), the probability that a randomly selected person ate 5 meals yesterday.
\[ P(X = 5) = \_\_\_\_ \]
(b) Find \( P(X \leq 2) \), the probability that a randomly selected person ate 2 or fewer meals yesterday.
\[ P(X \leq 2) = \_\_\_\_ \]
(c) Find the probability that a randomly selected person ate 1 meal or ate 5 meals yesterday.
\[ P = \_\_\_\_ \]
(d) Find \( P(X > 1) \), the probability that a randomly selected person ate more than 1 meal yesterday.
\[ P(X > 1) = \_\_\_\_ \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec13ab4f-5933-4c78-80c6-824491a34faa%2Fbafb523f-61bd-4271-86dd-1e26d1cee5ec%2Fxvl3qd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For a large population of people, the probability distribution for the random variable \( X \) (the number of meals a person ate yesterday) and the assigned probabilities is given below:
| Meals, \( X \) | 1 | 2 | 3 | 4 | 5 |
|-------------------|-----|-----|-----|-----|-----|
| Probability | 0.17| 0.35| 0.24| 0.17| ? |
### Questions
(a) Find \( P(X = 5) \), the probability that a randomly selected person ate 5 meals yesterday.
\[ P(X = 5) = \_\_\_\_ \]
(b) Find \( P(X \leq 2) \), the probability that a randomly selected person ate 2 or fewer meals yesterday.
\[ P(X \leq 2) = \_\_\_\_ \]
(c) Find the probability that a randomly selected person ate 1 meal or ate 5 meals yesterday.
\[ P = \_\_\_\_ \]
(d) Find \( P(X > 1) \), the probability that a randomly selected person ate more than 1 meal yesterday.
\[ P(X > 1) = \_\_\_\_ \]
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