For the probability distribution, find a. X b. P(y> 2) c. F(y = 6) d. Du 0.05, 0.10, f(y)= 0.15, 0.20, X, y = -2 y = -1 y = 0 y = 1 y = 2

Q: Find the probability​ P(E or​ F) if E and F are mutually​ exclusive, ​P(E)=0.34​, and ​P(F)=0.47.

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Q: P(A u B) = 0.4 and P(A n B) = 0.2. Find P(A) + P(B).

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Q: Given P(A)=0.4, P(A'|B1)=.8, finish the probability table:   B1 B2 B3 A 0.2   0.1 A'   0.1

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Q: For a probability distribution X, if E(X) = 0.35 then E(3X-2) = Select one: O 1.05 O -1.05 O 0.95 O…

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Q: Find the probability​ P(E or​ F) if E and F are mutually​ exclusive, ​P(E)=0.54, and ​P(F)=0.29.

A: GivenE and F are mutually exclusiveP(E)=0.54P(F)=0.29

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Q: Use the given information to find the indicated probability. P(A) = 0.70. Find P(A'). P(A') =

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A: Addition rule will applied here