A communication satellite appears stationary from a place on the equator. Find the height of the satellite from the surface of the earth. G = 6.7 x 10-1¹ M. K. S. units. Mass of earth = 6 x 10 kg, Radius of earth = 64000 km.
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- 2. Determine the following. a. What is the acceleration due to gravity on the surface of the Moon? Hint: see index D in the textbook for the necessary values needed. b. On the surface of Mars? The mass of Mars is 6.418 × 1023 kg and its radius is 3.38 × 106 m.The Moon has a mass 7.35 x 1022 kg of and a radius of 1740 km. Air resistance can be neglected on the Moon. G = 6.67 x 10-11 m3 kg-1 s-2 is the universal gravitational constant. (a) If a ball is launched upwards from the surface of the moon with an initial speed of 1.15 km/s, what height maximum height above the surface of the moon will it reach? Give your answer in kilometers. (b) What is the escape speed of the moon? Give your answer in km/s.9.) Please help with equation, gravity is g= 9.81 m/sec^2 or 32.2 ft/sec^2
- A 4.4 kg mass weighs 35.64 N on the surfaceof a planet similar to Earth. The radius ofthis planet is roughly 6 × 10^6 m.Calculate the mass of of this planet. Thevalue of the universal gravitational constantis 6.67259 × 10^−11 N · m^2/kg^2.Answer in units of kg. Calculate the average density of this planet.Answer in units of kg/m^3.The International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 10 24 kg, the period of the ISS at the orbit around the earth is 9.16 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles? Use G=6.674 x 10 -11 Nm2/kg2. Write your answer in pure numbers, for example, 4567.8. Please keep at least on digit after the decimal point.Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.4 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem: mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2 1.)What is the force of attraction between Mars and the satellite? 2.)What speed should the satellite have to be in a perfectly circular orbit? 3.)How much time does it take the satellite to complete one revolution?
- A sphere of copper has a radius of 50.0 cm and a mass of 4690 kg. A sphere of unknown metal has a radius of 30.0 cm. The surfaces of the spheres are 20.0 cm apart. The force of gravitational attraction between the two spheres is 0.372 mN. What is the mass of the unknown metal?The mass of planet X is 6.4 x 1023 kg and the aceleration of gravity on its surface is 3.7 m/s², if the gravitational constant G = 6.67 x 10-11 N.m²/kg², the radius of this planet R is a) 3.40 x 106 m c) 4.03 x 106 m e) 1.15 x 1013 m b) 2.98 x 106 m d) 7.56 x 106 m.3. The gravitational acceleration at Earth's surface (ga) is about 10 m/s? and ge = GM/R2. What is g, at the surface of a planet with 2X Earth's mass and 3X Earth's radius?