9. Calculate the centripetal acceleration of the Earth due to the gravitational pull of the Sun. Earth mass=597x1024 Sun mass=1.99x1030 kg Earth's orbit radius= 1.50 X10" m
9. Calculate the centripetal acceleration of the Earth due to the gravitational pull of the Sun. Earth mass=597x1024 Sun mass=1.99x1030 kg Earth's orbit radius= 1.50 X10" m
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Question
9.) Please help with equation, gravity is g= 9.81 m/sec^2 or 32.2 ft/sec^2
![**Problem 9: Calculating Centripetal Acceleration**
Calculate the centripetal acceleration of the Earth due to the gravitational pull of the Sun.
**Given Data:**
- Earth mass \( = 5.97 \times 10^{24} \, \text{kg} \)
- Sun mass \( = 1.99 \times 10^{30} \, \text{kg} \)
- Earth's orbit radius \( = 1.50 \times 10^{11} \, \text{m} \)
This problem involves finding the centripetal acceleration of the Earth as it orbits the Sun. You will use the given data to apply relevant physics equations to determine this acceleration. No graphs or diagrams are included here.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3738e16a-10fd-4378-b4a3-b8733d2d5bb5%2F97f09919-0945-4e5c-a3ad-4066380b7fdc%2Fvm3cbbk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 9: Calculating Centripetal Acceleration**
Calculate the centripetal acceleration of the Earth due to the gravitational pull of the Sun.
**Given Data:**
- Earth mass \( = 5.97 \times 10^{24} \, \text{kg} \)
- Sun mass \( = 1.99 \times 10^{30} \, \text{kg} \)
- Earth's orbit radius \( = 1.50 \times 10^{11} \, \text{m} \)
This problem involves finding the centripetal acceleration of the Earth as it orbits the Sun. You will use the given data to apply relevant physics equations to determine this acceleration. No graphs or diagrams are included here.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given
Mass of earth Me = 5.97 x 1024 Kg
Mass of Sun Ms = 1.99 x 1030 Kg
The radius of the earths orbit is R = 1.50 x 1011 m
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Solved in 3 steps
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