I need help on this question? G=10m/s^2 **Problem 6.2:**A baseball pitcher throws a pitch horizontally at 30 m/s. Assuming air friction is negligible (which is often not a good assumption in baseball), how far will the ball have dropped by the time it crosses home plate 18.3 m away?**Solution Explanation:**This problem involves projectile motion. We know that the ball is thrown horizontally, meaning its initial vertical velocity is 0 m/s. We need to determine how far it drops vertically over the horizontal distance to the home plate.1. **Given:** - Horizontal velocity, \( v_x = 30 \, \text{m/s} \) - Horizontal distance, \( d_x = 18.3 \, \text{m} \) - Acceleration due to gravity, \( g = 9.81 \, \text{m/s}^2 \)2. **Calculate the time to reach home plate:** \[ t = \frac{d_x}{v_x} = \frac{18.3}{30} = 0.61 \, \text{s} \]3. **Vertical motion:** - Initial vertical velocity, \( v_{y0} = 0 \) - Vertical displacement, \( y \)4. **Using the equation for vertical displacement:** \[ y = v_{y0} \cdot t + \frac{1}{2} g t^2 = 0 + \frac{1}{2} \cdot 9.81 \cdot (0.61)^2 \] \[ y \approx 1.83 \, \text{m} \]**Conclusion:**The baseball will have dropped approximately 1.83 meters by the time it crosses home plate.

Name: I need help on this question? G=10m/s^2 **Problem 6.2:**A baseball pit
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: I need help on this question? G=10m/s^2 **Problem 6.2:**A baseball pitcher throws a pitch horizontally at 30 m/s. Assuming air friction is negligible (which is often not a good assumption in baseball), how far will the ball have dropped by the time i