A combinatorial digital system requires the comparison of two vectors X and Y of 4 bits each.one being necessary to obtain the signal that indicates when X is less than or equal to Y. Present aclear diagram of how you would use the 7485 and additional gates to get that signal.Below is the symbol for 7485X = X3,X2,X1,X0 Y = Y3,Y2,Y1,Y0 A continuación el símbolo para el 7485X = X3, X2, X₁, XoY=Y3,Y2,Y₁, Yo04 03 0₂ 01Em7485>_inD4 D3 D₂ D₁ Outout Un sistema digital combinatorio requiere realizar la comparación de dos vectores Xy Y de 4 bits cadauno siendo necesario obtener la señal que indique cuando X sea menor o igual Y. Presente undiagrama claro de como usaría el 7485 y compuertas adicionales para obtener dicha señal.A continuación el símbolo para el 7485X = X3, X2, X1, XoY = Y3,Y2,Y1,Yoa4 a3 a2 a1<_in> in7485=_inD4 D3 D₂ D₁<_out > _out =_out

To design:a combinational system that compares the two binary 4-bit numbers and using 7485 IC. we…

Answered: A combinatorial digital system requires…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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A combinatorial digital system requires the comparison of two vectors X and Y of 4 bits each.
one being necessary to obtain the signal that indicates when X is less than or equal to Y. Present a
clear diagram of how you would use the 7485 and additional gates to get that signal.
Below is the symbol for 7485

X = X3,X2,X1,X0 Y = Y3,Y2,Y1,Y0

A continuación el símbolo para el 7485
X = X3, X2, X₁, Xo
Y=Y3,Y2,Y₁, Yo
04 03 0₂ 01
Em
7485
>_in
D4 D3 D₂ D₁
<out > Out
out

Un sistema digital combinatorio requiere realizar la comparación de dos vectores Xy Y de 4 bits cada
uno siendo necesario obtener la señal que indique cuando X sea menor o igual Y. Presente un
diagrama claro de como usaría el 7485 y compuertas adicionales para obtener dicha señal.
A continuación el símbolo para el 7485
X = X3, X2, X1, Xo
Y = Y3,Y2,Y1,Yo
a4 a3 a2 a1
<_in
> in
7485
=_in
D4 D3 D₂ D₁
<_out > _out =_out

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