A circular foundation of diameter 8 m supports a tank. The base of the foundation is at 1 m below the ground surface. The vertical load is 20 MN. The tank foundation is supported by a soil with undrained shear strength equal to 80 kPa and saturated unit weight of 19 kN/m3, dry unit weight of 17.6 kN/m3 and angle of internal friction equal to 25°. Ground water table is 4 meters below the surface and assumed to be stable. Fourteen months after the tank was constructed, during a week of intense rainfall, the foundation failed. It was speculated that failure occurred by bearing capacity failure. Clarify whether this is so or not.

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Q: after the tank

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Q: . It was speculated that failure occurred by bearing capacity failure. Clarify whether this is so or…

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Q: a) Find the allowable load on the foundation by Terzaghi method, assuming a general shear failu with…

A: Answer Net allowable load = Qall  Cohesion C =13 kpa Dry Unit weight of soil (γd) =17 Kn/m3…

Q: Question Attached

A: Given:-γsat=18.5kN/m3w=22%q=100kN/m220mdry sand =3mGs=2.70Cc=0.30Size = 20m x 20mγ=17.5kN/m3To…

Q: A circular foundation of diameter 8m supports a tank. The base of the foundation is at 1m below the…

A: Solution:-   Given:- foundation diameter D=8m                 vertical load=20HN…

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A: Given, Depth of water table = 2 m  Depth of water table = 5 m

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Q: rectangular footing 3 × 2 cted to a moment of 90 kNm

A: Given data Rectangular footing= 3×2m Column=420×420mm E=21×103kN/m2 μ=0.3

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A: The formula to calculate the average elastic settlement is given by, Se=A1A2q0BEs…

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A: A rectangular foundation 1.5m x 2.0m located at a depth of 2 meters below the groundbelow the…

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A: Given data: γdsand=15.5 kN/m3γsatsand=19.2 kN/m3γsatclay=18.8 kN/m3

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Q: A building has to be supported over a raft foundation of dimensions 15 m x 25 m. The soil is clay…

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Q: Calculate the settlement due to volume distortion in a clay where a rectangular-shape (flexible…

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Q: 11.44 A circular raft foundation of 20 m diameter and 1.6 m thick is provided for a tank that…

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Q: 11.44 A circular raft foundation of 20 m diameter and 1.6 m thick is provided for a tank that…

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Q: Find the stress beneath Point B of the 40 ft by 80 ft. L-Shaped flexible 1) mat foundation at depth…

A: Given Data: Size of Mat is 40 ft x 80 ft. Mat loading is w=200 psf. Depth Z=20 ft.

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Q: 80' B 20 200 psf 40! 20 60

A: tan2θ =6020 2θ =1.249 radian Stress beneath point B due to portion1 σz = qπ[2θ+sin2θ]      =…

Q: Civil Engineering A multistory building with a basement is to be constructed. The top 4 m consists…

A: Given- Width of basement slab = 6 m,Es=60×103 KPa,μ=0.3,Influence factor I.F=2, It is needed to find…

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Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.