A child gets a weekly allowance (a certain non-negative number of dollars). The amount (in dollars) is random with expectation equal to 6 and variance equal to 6. Let’s denote this random variable by X. I want to estimate (from above) the chances that the child gets 10 dollars or more on a given week. In other words, I want to find c such that P(X ≥ 10) ≤ c, with c that is as small as possible. (a) Use the Markov inequality to find c such that P(X ≥ 10) ≤ c. (b) Use the Chebyshev inequality for the variance to find c such that P(X ≥ 10) ≤ c. (c) Read about the one-sided Chebyshev inequality, and use it to find c such that P(X ≥ 10) ≤ c.

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A child gets a weekly allowance (a certain non-negative number of dollars). The amount (in dollars) is random with expectation equal to 6 and variance equal to 6. Let’s denote this random variable by X. I want to estimate (from above) the chances that the child gets 10 dollars or more on a given week. In other words, I want to find c such that P(X ≥ 10) ≤ c, with c that is as small as possible.
(a) Use the Markov inequality to find c such that P(X ≥ 10) ≤ c.
(b) Use the Chebyshev inequality for the variance to find c such that P(X ≥ 10) ≤ c.
(c) Read about the one-sided Chebyshev inequality, and use it to find c such that P(X ≥ 10) ≤ c.

Expert Solution
Step 1

Given that

The expectation  =  6

The variance        =  6

The child wants to find P(X10)c  using

  • the Markov inequality
  • The Chebyshev inequality for the variance
  • The one-sided  Chebyshev inequality
Step 2

Markov inequality:

If X is a random variable then the Markov inequality for discrete and mixed random variables 

P(Xa)E(X)a

Chebyshev's inequality:

If X is a random variable and a>0 then Chebyshev's inequality  is 

P(|X-E(X)a)var(x)a2


One-Sided Chebyshev: For any positive number a > 0, the following one-sided Chebyshev inequalities hold

P(XE(x)+a)var(x)a2+var(x)

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