The random variable X is distributed normally with mean µx and variance 6, and the random variable Y is normally distributed with mean 8 and variance of. 2X – 3Y is distributed normally with mean 12 and variance 42. Calculate the values of µx and oy respectively. Assume independence! O a. Hx = - 6 and oy=2 O b. Hx = 18 and oy=2 O C. Hx = 6 and oy=2 O d. Hx= 12 and oy=42

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Chapter1: Combinatorial Analysis
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The problem statement is as follows:

"The random variable \( X \) is distributed normally with mean \( \mu_X \) and variance 6, and the random variable \( Y \) is normally distributed with mean 8 and variance \( \sigma_Y^2 \). \( 2X - 3Y \) is distributed normally with mean 12 and variance 42.

Calculate the values of \( \mu_X \) and \( \sigma_Y \) respectively. Assume independence!"

Options provided are:

- a. \( \mu_X = -6 \) and \( \sigma_Y = 2 \)
- b. \( \mu_X = 18 \) and \( \sigma_Y = \sqrt{2} \)
- c. \( \mu_X = -6 \) and \( \sigma_Y = \sqrt{2} \)
- d. \( \mu_X = 12 \) and \( \sigma_Y = \sqrt{42} \)
Transcribed Image Text:The problem statement is as follows: "The random variable \( X \) is distributed normally with mean \( \mu_X \) and variance 6, and the random variable \( Y \) is normally distributed with mean 8 and variance \( \sigma_Y^2 \). \( 2X - 3Y \) is distributed normally with mean 12 and variance 42. Calculate the values of \( \mu_X \) and \( \sigma_Y \) respectively. Assume independence!" Options provided are: - a. \( \mu_X = -6 \) and \( \sigma_Y = 2 \) - b. \( \mu_X = 18 \) and \( \sigma_Y = \sqrt{2} \) - c. \( \mu_X = -6 \) and \( \sigma_Y = \sqrt{2} \) - d. \( \mu_X = 12 \) and \( \sigma_Y = \sqrt{42} \)
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