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The number of customers visiting a store during a day is a random variable with mean EX and variance Var(X) = 225. = 100 1. Using Chebyshev's inequality, find an upper bound for having more than 120 or less than 80 customers in a day. That is, find an upper bound on P(X ≤ 80 or X ≥ 120). 2. Using the one-sided Chebyshev inequality (Problem 21), find an upper bound for having more than 120 customers in a day.

The number of customers visiting a store during a day is a random variable with mean EX and variance Var(X) = 225. = 100 1. Using Chebyshev's inequality, find an upper bound for having more than 120 or less than 80 customers in a day. That is, find an upper bound on P(X ≤ 80 or X ≥ 120). 2. Using the one-sided Chebyshev inequality (Problem 21), find an upper bound for having more than 120 customers in a day.

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
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The number of customers visiting a store during a day is a random variable with mean EX = 100 and variance Var(X) = 225. 1. Using Chebyshev's inequality, find an upper bound for having more than 120 or less than 80 customers in a day. That is, find an upper bound on P(X ≤ 80 or X ≥ 120). 2. Using the one-sided Chebyshev inequality (Problem 21), find an upper bound for having more than 120 customers in a day.
Transcribed Image Text:The number of customers visiting a store during a day is a random variable with mean EX = 100 and variance Var(X) = 225. 1. Using Chebyshev's inequality, find an upper bound for having more than 120 or less than 80 customers in a day. That is, find an upper bound on P(X ≤ 80 or X ≥ 120). 2. Using the one-sided Chebyshev inequality (Problem 21), find an upper bound for having more than 120 customers in a day.
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