Find the mean and variance for the probability distribution given by f(x)= 2x k(k+1)* -,x=1,2,3,...k
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![Find the mean and variance for the probability distribution given by
f(x)=
2x
k(k+1)*
-,x=1,2,3,...k](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2844e9b7-fdae-4ffb-b3b7-8f54bdb6d500%2F5abd5245-3f97-42bf-8fef-43a86dcaf138%2Fusmq55w_processed.png&w=3840&q=75)
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- A bus heading to university is always scheduled to arrive at a certain bus stop at 7:30am. The difference between the actual arrival time and 7:30am is normally distributed with mean 0 and standard deviation of 2 minutes.A student who always has a class at 8am decided to be at the bus stop at 7:28am in order to try to guarantee catching this bus. What is the probability that the student will catch the bus on any particular day?Probability = What is the probability that the student will catch the bus at least 4 times out of 5 days?Probability =Today, the waves are crashing onto the beach every 4.9 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 4.9 seconds. Round to 4 decimal places where possible. The mean of this distribution is The standard deviation is The probability that wave will crash onto the beach exactly 0.6 seconds after the person arrives is P(x = 0.6) =Which distribution's height begins low, increases until the middle, and then decreases such that it has a steep side and a shallow side
- The area (in percentage) under standard normal distribution curve of random variable Z within limits from -3 to +3 is,Q2. (a) Show that the Poisson distribution is the limiting case of Binomial distribution. (b) The distribution of 40 workers in an office is approximately Normal with mean and standard deviation is Rs 110 and 30 respectively. Calculate the number of workers who receives weekly wages of more than 120 rupees.Suppose that f(x)=2/(3^x), x=1,2,3,... is the probability function for a random variable X. Find P(X>3). Use 4 decimal places.
- Today, the waves are crashing onto the beach every 5 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5 seconds. Round to 4 decimal places where possible. The mean of this distribution is The standard deviation is The probability that wave will crash onto the beach exactly 2 seconds after the person arrives is P(x = 2) = The probability that the wave will crash onto the beach between 0.4 and 2.9 seconds after the person arrives is P(0.4 < x < 2.9) = The probability that it will take longer than 1.5 seconds for the wave to crash onto the beach after the person arrives is P(x > 1.5) = Suppose that the person has already been standing at the shoreline for 1.3 seconds without a wave crashing in. Find the probability that it will take between 2.7 and 4.8 seconds for the wave to crash onto the shoreline. 27% of the time a person will wait at least how long before the wave crashes in?…Today, the waves are crashing onto the beach every 6 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 6 seconds. Round to 4 decimal places where possible. The mean of this distribution is The standard deviation is The probability that wave will crash onto the beach exactly 3.9 seconds after the person arrives is P(x = 3.9) =Today, the waves are crashing onto the beach every 5.1 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5.1 seconds. Round to 4 decimal places where possible. The mean of this distribution is The standard deviation is The probability that wave will crash onto the beach exactly 1.4 seconds after the person arrives is P(x = 1.4) = The probability that the wave will crash onto the beach between 1.3 and 4.7 seconds after the person arrives is P(1.3 < x < 4.7) = The probability that it will take longer than 3.92 seconds for the wave to crash onto the beach after the person arrives is P(x > 3.92) = Suppose that the person has already been standing at the shoreline for 1.1 seconds without a wave crashing in. Find the probability that it will take between 2.4 and 3.8 seconds for the wave to crash onto the shoreline. 84% of the time a person will wait at least how long before the wave crashes in?…
- I need the answer as soon as possiblePlease no written by hand and no emageQ7) The length of time, in seconds, that a computer user takes to read his or her e- mail is distributed as lognormal random variable with μ = 1.8 and o² = 4. (a) (b) What is the probability that a user reads e-mail for more than 20 seconds? More than a minute? What is the probability that a user reads e-mail for a length of time that is equal to the mean of the underlying lognormal distribution?
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