A chemist performed an experiment to determine the rate low for the reaction of permanganate ions with oxalic acid 3H2C204(aq) + 2MnO4¯(aq) → 6CO2(g) + 20H (aq) + 2H2O(1) + 2MnO2(s) Use the provided data in the table to determine the order and the rate law of this chemical reaction? Experiments Run 1 Run 2 Run 3 Oxalic acid 2.50 mL 5.00 mL 2.50 mL KMnO4 0.50 mL 0.50 mL 1.0 mL Distilled water 3.00 mL 0.50 mL 2.50 mL Concentration of Oxalic acid in mixture Concentration of KMnO4 in mixture Elapsed time (min) 6.44 3.20 6.46 Concentration of stock solution of oxalic acid = 0.1 M Concentration of stock solution of potassium permanganate = 0.05 M %3D Recorded Temp. = 25 °C.

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A chemist performed an experiment to determine the rate low for the reaction of permanganate ions with oxalic acid
3H2C204(aq) + 2MnO4 (aq) → 6CO2(g) + 20OH (aq) + 2H2O) + 2MnO2(s)
Use the provided data in the table to determine the order and the rate law of this chemical reaction?
Experiments
Run 1
Run 2
Run 3
Oxalic acid
2.50 mL
5.00 mL
2.50 mL
KMN04
0.50 mL
0.50 mL
1.0 mL
Distilled water
3.00 mL
0.50 mL
2.50 mL
Concentration of Oxalic acid in
mixture
Concentration of KMN04 in
mixture
Elapsed time (min)
6.46
6.44
3.20
Concentration of stock solution of oxalic acid = 0.1 M
Concentration of stock solution of potassium permanganate = 0.05 M
%3D
Recorded Temp. = 25 °C.
%3D
Transcribed Image Text:A chemist performed an experiment to determine the rate low for the reaction of permanganate ions with oxalic acid 3H2C204(aq) + 2MnO4 (aq) → 6CO2(g) + 20OH (aq) + 2H2O) + 2MnO2(s) Use the provided data in the table to determine the order and the rate law of this chemical reaction? Experiments Run 1 Run 2 Run 3 Oxalic acid 2.50 mL 5.00 mL 2.50 mL KMN04 0.50 mL 0.50 mL 1.0 mL Distilled water 3.00 mL 0.50 mL 2.50 mL Concentration of Oxalic acid in mixture Concentration of KMN04 in mixture Elapsed time (min) 6.46 6.44 3.20 Concentration of stock solution of oxalic acid = 0.1 M Concentration of stock solution of potassium permanganate = 0.05 M %3D Recorded Temp. = 25 °C. %3D
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