A value of k is found from the rate equation Rate = k[A]m[B]". If m=3 and n=3 and the unit for the initial rate is M/h. The unit of k is found to be MX h¯1 (M to the power of x h to the power of minus 1). What is the value of x?

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### Determining the Value of \( x \) in the Rate Equation

Consider a reaction whose rate equation is given by:

\[ \text{Rate} = k[\text{A}]^m[\text{B}]^n \]

Given parameters:
- \( m = 3 \)
- \( n = 3 \)
- The unit of the initial rate is \( \frac{\text{M}}{\text{h}} \) (molarity per hour).

We need to determine the unit for the rate constant \( k \), which is provided as \( \text{M}^x \text{h}^{-1} \). Here, \( \text{M} = \text{molarity} \) (moles per liter).

### Steps to Determine \( x \):

1. **Understand the units of each component in the rate equation**:
    - \(\text{Rate}\) has the unit \( \frac{\text{M}}{\text{h}} \).
    - \([\text{A}]\) and \([\text{B}]\) each have units \( \text{M} \).

2. **Express the rate equation with units**:
    \[ \frac{\text{M}}{\text{h}} = k (\text{M})^3 (\text{M})^3 \]
    Simplifying, we get:
    \[ \frac{\text{M}}{\text{h}} = k (\text{M})^6 \]

3. **Determine the units of \( k \)**:
    Rearrange to solve for \( k \):
    \[ k = \frac{\frac{\text{M}}{\text{h}}}{\text{M}^6} \]
    Simplify:
    \[ k = \text{M}^{1-6} \text{h}^{-1} \]
    \[ k = \text{M}^{-5} \text{h}^{-1} \]

4. **Conclusion**:
    The unit of \( k \) is \( \text{M}^{x} \text{h}^{-1} \), where \( x = -5 \).

Thus, the value of \( x \) is \( -5 \).
Transcribed Image Text:### Determining the Value of \( x \) in the Rate Equation Consider a reaction whose rate equation is given by: \[ \text{Rate} = k[\text{A}]^m[\text{B}]^n \] Given parameters: - \( m = 3 \) - \( n = 3 \) - The unit of the initial rate is \( \frac{\text{M}}{\text{h}} \) (molarity per hour). We need to determine the unit for the rate constant \( k \), which is provided as \( \text{M}^x \text{h}^{-1} \). Here, \( \text{M} = \text{molarity} \) (moles per liter). ### Steps to Determine \( x \): 1. **Understand the units of each component in the rate equation**: - \(\text{Rate}\) has the unit \( \frac{\text{M}}{\text{h}} \). - \([\text{A}]\) and \([\text{B}]\) each have units \( \text{M} \). 2. **Express the rate equation with units**: \[ \frac{\text{M}}{\text{h}} = k (\text{M})^3 (\text{M})^3 \] Simplifying, we get: \[ \frac{\text{M}}{\text{h}} = k (\text{M})^6 \] 3. **Determine the units of \( k \)**: Rearrange to solve for \( k \): \[ k = \frac{\frac{\text{M}}{\text{h}}}{\text{M}^6} \] Simplify: \[ k = \text{M}^{1-6} \text{h}^{-1} \] \[ k = \text{M}^{-5} \text{h}^{-1} \] 4. **Conclusion**: The unit of \( k \) is \( \text{M}^{x} \text{h}^{-1} \), where \( x = -5 \). Thus, the value of \( x \) is \( -5 \).
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