A chemist dissolves 382. mg of pure sodium hydroxide in enough water to make up 70. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Round your answer to 2 significant decimal places.

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A chemist dissolves 382. mg of pure sodium hydroxide in enough water to make up 70. mL of solution. Calculate the pH of the solution. (The temperature of the
solution is 25 °C.)
Round your answer to 2 significant decimal places.
Transcribed Image Text:A chemist dissolves 382. mg of pure sodium hydroxide in enough water to make up 70. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Round your answer to 2 significant decimal places.
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Step 1

Solution :

We need to calculate the molarity of the solution first

1M NaOH=40g of NaOH in 1 L of solution 

70 mL= 0.07L of NaOH solution

0.382 g of NaOH is 0.382g/40g/mole= 0.00955 moles of NaOH per 0.07L=0.136mole/L=136 mol/m3

 

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