A certain material was tested for tension using three different specimens.For each trial, the load at the proportional limit was recorded together withthe corresponding elongated length of the specimen.GaugeLength(mm)MeasuredDiameterTrialLoad (kN)Length(mm)(mm)15010850.02565152065.039385203085.038Determine the average values of the moduli of elasticity and resilience forthe material.

Answered: Image /qna-images/answer/5e3a7855-d2c2-441b-9882-a82fb6440d6b.jpg

A certain material was tested for tension using three different specimens. For each trial, the load at the proportional limit was recorded together with the corresponding elongated length of the specimen. Gauge Length Measured Diameter Trial Load (kN) Length (mm) (mm) (mm) 1 50 10 50.02: 2 65 15 20 65.039 3 85 20 30 85.038 Determine the average values of the moduli of elasticity and resilience for the material.

A certain material was tested for tension using three different specimens. For each trial, the load at the proportional limit was recorded together with the corresponding elongated length of the specimen. Gauge Length Measured Diameter Trial Load (kN) Length (mm) (mm) (mm) 1 50 10 50.02: 2 65 15 20 65.039 3 85 20 30 85.038 Determine the average values of the moduli of elasticity and resilience for the material.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

I. Problem Solving: Answer what is being required. Show you complete solution. 1. Compute the compressive stress for the respective ages of the specimen. The diameter of the specimens is 150mm and the height is 300mm. Load (N) 176,000 Stress (MPa) Age 7days 14 days 28 days 252,000 340,000 2. Compute the tensile stress from the value acquired from the experiment if the breaking load is 105KN. The diameter of the specimen is 150mm and the height is 300mm. 3. Compute the flexural stress of the sample specimen if its dimension is 150mm x 150mm x 500mm in a 3 point loading. The effective length is 400mm. The specimen failed at 44,300N in the middle third. 4. Compression test was applied to a certain type of wood. Compute the stress based on the following dimensions. The grains are parallel with the length. а. Dimension (mm) Load (N) Compressive stress (МРа) Compression Test
The thin square plate shown is uniformly deformed such that €, = +1445 pE, E, = -674 uE, and y,y = +1260 urad. Determine the normal strain e, in the plate. 60 mm O -157 µE O -309 µE O -198 HE O -244 µE O -256 HE
Sem 2021-2022 A specimen is originally 1.5 ft long, has a diameter of o.7 in. and is subjected to a force 55olb. When the force is increased to 1900 lb, the specimen elongates o.g in. Determine the strain on the specimen and the modulus of elasticity for the material a. Strain ANSWER: in./in. b. Modulus of Elasticity ANSWER: ksi Next pag EVIOUS ACTIVITY term Quiz 1 NEXT ACTIVITY Midterm Exam >> Jump to. ype here to search
Asap
In a tensile test for an aluminum alloy, the sample used is 2 inches long and 0.5 inches in diameter. The proportional portion of the tension stress-strain diagram for an aluminum alloy is shown below. Determine the modulus of elasticity for this material: ____x106 lb/in2. Pay attention to units and calculate your answer to 1 decimal place for the unit specified above.
The strain rosette shown in the figure was used to obtain the following normal strain data on a piece of aluminum. The plate has a modulus of elasticity of 10,000 ksi and a Poisson’s Ratio of 0.35. The strain readings were εa = 600 με, εb = 900 με, and εc = 120 με. Note: 1 με = 1 X 10-6 in/in. a) Calculate the normal strain in the x- and y- directions (εx and εy) and the shear strain (γxy) using a system of equations. b) Calculate the normal stress σx in ksi. Clearly indicate Tension (T) or Compression (C). Note: even though the normal stress in the z-direction is zero, but the normal strain in the z-direction is NOT zero. [Ans. to Check σx = 7.18 ksi (T)] c) Calculate the normal stress σy in ksi. Clearly indicate Tension (T) or Compression (C). d) Calculate the shear stress τxy in ksi.
During a tensile test on a specimen the following results were obtainedload(KN) 15 30 40 50 55 60 65 70 75 80 82 80 70extension(mm) 0.05 0.094 0.127 0.157 1.778 2.79 3.81 5.08 7.62 12.7 16 19.05 22.9diameter of gauge length=19mmdiameter at fracture=16.49mmgauge length=100mmgauge lengthat fracture=121mmplot the complete load extension graph and the straight line portion to an enlarged scale .hence determinethe modulus of elasticitythe percentage elongationthe percentage reduction in areathe nominal stress at fracturethe actual stress at fracturethe tensile strength
Solid mechanics
A specimen is originally lft long, has a diameter of 0.5in, and is subjected to a force of 5001b. When the force is increased from 5001b to 1,8001b, the specimen elongates 0.009in. Determine the modulus of elasticity (2 decimal places in 103 ksi) for the material if it remains linear elastic.
Please answer this quick
A steel rod, 10mm in diameter and 150mm long is subjected to a tensile load of 50,000N. After the test, the length increases to 150.50mm with no appreciable decrease in diameter. Determine the modulus of elasticity of the steel, assuming that the material remains within the linear elastic region.
Urgent , Handwritten solution. Don't copy paste