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A certain liquid X has a normal freezing point of -9.40 °C and a freezing point depression constant 1 = 4.04 °C kg mol. A solution is prepared by dissolving some iron(III) chloride (FeCl,) in 150. g of X. This freezes at - 13.0 °C. Calculate the mass of FeCl, that was dissolved. Round your answer to 2 significant digits.

A certain liquid X has a normal freezing point of -9.40 °C and a freezing point depression constant 1 = 4.04 °C kg mol. A solution is prepared by dissolving some iron(III) chloride (FeCl,) in 150. g of X. This freezes at - 13.0 °C. Calculate the mass of FeCl, that was dissolved. Round your answer to 2 significant digits.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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A certain liquid X has a normal freezing point of – 9.40 °C and a freezing point depression constant K,=4.04 °C kg•mol 1 . A solution is prepared by dissolving some iron(III) chloride (FeCl,) in 150. g of X. This solution freezes at - 13.0 °C. Calculate the mass of FeCl, that was dissolved. Round your answer to 2 significant digits. do Ar Check Explanation Terms of Use Privacy Center | Accessibility ©2022 McGraw Hill LLC. All Rights Reserved. FEB tv 3.
Transcribed Image Text:A certain liquid X has a normal freezing point of – 9.40 °C and a freezing point depression constant K,=4.04 °C kg•mol 1 . A solution is prepared by dissolving some iron(III) chloride (FeCl,) in 150. g of X. This solution freezes at - 13.0 °C. Calculate the mass of FeCl, that was dissolved. Round your answer to 2 significant digits. do Ar Check Explanation Terms of Use Privacy Center | Accessibility ©2022 McGraw Hill LLC. All Rights Reserved. FEB tv 3.
Expert Solution
Step 1

Given a liquid X,Normal freezing point = -9.40°CFreezing point of solution = -13.0°CDepression in freezing point(∆Tf) = 3.60°CKf=4.04 °C Kg mol-1Mass of solvent =150×10-3Kg

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