(a) Calculate the retarding force (in N) due to the viscosity of the air layer between a cart and a level air track given the following information-air temperature is 20°C, the cart is moving at 0.350 m/s, its surface area is 2.50 x 10-2 m2, and the thickness of the air layer is 6.00 x 10- m. N (b) What is the ratio of this force to the weight of the 0.300 kg cart?
Fluid Pressure
The term fluid pressure is coined as, the measurement of the force per unit area of a given surface of a closed container. It is a branch of physics that helps to study the properties of fluid under various conditions of force.
Gauge Pressure
Pressure is the physical force acting per unit area on a body; the applied force is perpendicular to the surface of the object per unit area. The air around us at sea level exerts a pressure (atmospheric pressure) of about 14.7 psi but this doesn’t seem to bother anyone as the bodily fluids are constantly pushing outwards with the same force but if one swims down into the ocean a few feet below the surface one can notice the difference, there is increased pressure on the eardrum, this is due to an increase in hydrostatic pressure.
![(a) Calculate the retarding force (in N) due to the viscosity of the air layer between a cart and a level air track given the following information—air temperature is 20°C, the cart is moving at 0.350 m/s, its surface area is 2.50 × 10⁻² m², and the thickness of the air layer is 6.00 × 10⁻⁵ m.
[Box for answer] N
(b) What is the ratio of this force to the weight of the 0.300 kg cart?
[Box for answer]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd52694c2-08a6-4e13-96ed-a87f03e48e22%2F676baef2-bf41-4449-822c-fec9dd466e80%2Ftn9dl6j_processed.jpeg&w=3840&q=75)
Given data
*The surface area of the cart is A = 2.50 × 10-2 m2
*The given speed of the cart is v = 0.350 m/s
*The given thickness is t = 6.00 × 10-5 m
*The coefficient of viscosity of air is
*The given mass of the cart is m = 0.300 kg
(a)
The expression for the retarding force is given as,
Substitute the values in the above expression as
Thus the regarding force is Fr = 2.6 × 10-3 N
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