A buffer was created using ascorbic acid and sodium ascorbate. What is the pH of the buffered solution if at equilibrium [H₂C6H6O6] = 5.5 X 105 M, [HC6H606¹] =3.5 X 104 M, and K, = 8.00 x 10-5 everything is based upon the acid dissolving in water: H₂C6H6O6 + H₂O <-> HC6H₂O6¹¹ + H₂O+1 [ I K₂ solve for [H3O+1] then put in the numbers. Ka [ [H3O+¹] = [ J] X [H3O+¹] = pH = -log a. H30*1 b. OH-1 h. HCzH3Oz i. C₂H30₂¹¹ c. H₂C6H6O6 d. HC6H606¹ j. H₂S k. HS-1 q. 3 r. 0.5000 s. 5.5 X 10.5 t. 3.5 X 10.4 x. 5.5 x 10-2 y. 0.7000 z. 1.60 x 10-5 aa. dd. 0.7100 ee. 1.26 x 10-5 ff. 4.901 gg. 7.93 hh. 4.942 ii. 4.957 f. SO3² g. H₂SO3 m. HX n. X-1 o. 1 p. 2 e. HSO3¹¹ 1. S-2 u. 8.00 x 10-5 v. 1.75 x 10-6 W. 1.11 x 10.8 1.143 x 105 bb. 0.4900 cc. 1.104 x 10-5
A buffer was created using ascorbic acid and sodium ascorbate. What is the pH of the buffered solution if at equilibrium [H₂C6H6O6] = 5.5 X 105 M, [HC6H606¹] =3.5 X 104 M, and K, = 8.00 x 10-5 everything is based upon the acid dissolving in water: H₂C6H6O6 + H₂O <-> HC6H₂O6¹¹ + H₂O+1 [ I K₂ solve for [H3O+1] then put in the numbers. Ka [ [H3O+¹] = [ J] X [H3O+¹] = pH = -log a. H30*1 b. OH-1 h. HCzH3Oz i. C₂H30₂¹¹ c. H₂C6H6O6 d. HC6H606¹ j. H₂S k. HS-1 q. 3 r. 0.5000 s. 5.5 X 10.5 t. 3.5 X 10.4 x. 5.5 x 10-2 y. 0.7000 z. 1.60 x 10-5 aa. dd. 0.7100 ee. 1.26 x 10-5 ff. 4.901 gg. 7.93 hh. 4.942 ii. 4.957 f. SO3² g. H₂SO3 m. HX n. X-1 o. 1 p. 2 e. HSO3¹¹ 1. S-2 u. 8.00 x 10-5 v. 1.75 x 10-6 W. 1.11 x 10.8 1.143 x 105 bb. 0.4900 cc. 1.104 x 10-5
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![A buffer was created using ascorbic acid and sodium ascorbate. What is the pH of the buffered solution if at equilibrium [H₂C6H6O6] = 5.5 X 10-5 M, [HC6HO6¹¹] = 3.5 X 104 M, and K₂ = 8.00 x 10-5 ?
everything is based upon the acid dissolving in water:
H₂C6H6O6 + H₂O <-> HC6H6O6¹¹ + H3O+1
[
|][
Ka =
[
solve for [H3O+¹] then put in the numbers
Ka [
[H3O+¹] =
[
[H3O+¹] =
pH = -log
a. H30+1
b. OH-1
h. HCzH3O2 i. C₂H3O₂-¹
=
c. H₂C6H6O6
q. 3 r. 0.5000 s. 5.5 X 10-5
x. 5.5 x 10-²
dd. 0.7100
]
y. 0.7000
z. 1.60 x 10-5
ee. 1.26 x 10-5 ff. 4.901
(
d. HC6H606¹¹
j. H₂S k. HS-1
t. 3.5 X 10-4
-1
e. HSO3¹¹
1. S-²
X(
m. HX
f. SO3²
n. X-1
g. H₂SO3
o. 1 p. 2
W. 1.11 x 10-8
u. 8.00 x 10-5
v. 1.75 x 10-6
aa. 1.143 x 105 bb. 0.4900 cc. 1.104 x 10-5
gg. 7.93 hh. 4.942 ii. 4.957](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feab2d2d3-91b0-42ef-9603-f34b4b53ecf8%2F7e4b65b6-b6e3-4224-8c4a-b9621c7b60f1%2Fm1o43qf_processed.png&w=3840&q=75)
Transcribed Image Text:A buffer was created using ascorbic acid and sodium ascorbate. What is the pH of the buffered solution if at equilibrium [H₂C6H6O6] = 5.5 X 10-5 M, [HC6HO6¹¹] = 3.5 X 104 M, and K₂ = 8.00 x 10-5 ?
everything is based upon the acid dissolving in water:
H₂C6H6O6 + H₂O <-> HC6H6O6¹¹ + H3O+1
[
|][
Ka =
[
solve for [H3O+¹] then put in the numbers
Ka [
[H3O+¹] =
[
[H3O+¹] =
pH = -log
a. H30+1
b. OH-1
h. HCzH3O2 i. C₂H3O₂-¹
=
c. H₂C6H6O6
q. 3 r. 0.5000 s. 5.5 X 10-5
x. 5.5 x 10-²
dd. 0.7100
]
y. 0.7000
z. 1.60 x 10-5
ee. 1.26 x 10-5 ff. 4.901
(
d. HC6H606¹¹
j. H₂S k. HS-1
t. 3.5 X 10-4
-1
e. HSO3¹¹
1. S-²
X(
m. HX
f. SO3²
n. X-1
g. H₂SO3
o. 1 p. 2
W. 1.11 x 10-8
u. 8.00 x 10-5
v. 1.75 x 10-6
aa. 1.143 x 105 bb. 0.4900 cc. 1.104 x 10-5
gg. 7.93 hh. 4.942 ii. 4.957
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