An analytical chemist is titrating 205.8 mL of a 0.09100M solution of propylamine (C,H,NH,) with a 0.1800M solution of HNO. The p K, of propylamine is 3.46. Calculate the pH of the base solution after the chemist has added 110.6 mL of the HNO, solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO, solution added. Round your answer to 2 decimal places. pH = 0

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An analytical chemist is titrating 205.8 mL of a 0.0910 M solution of propylamine \((\text{C}_3\text{H}_7\text{NH}_2)\) with a 0.1800 M solution of \(\text{HNO}_3\). The \(pK_b\) of propylamine is 3.46. Calculate the pH of the base solution after the chemist has added 110.6 mL of the \(\text{HNO}_3\) solution to it.

*Note for advanced students:* you may assume the final volume equals the initial volume of the solution plus the volume of \(\text{HNO}_3\) solution added.

Round your answer to 2 decimal places.

---

\[ \text{pH} = \boxed{} \]

Below the text, there are buttons with an 'X' for clearing, a circular arrow for resetting, and a question mark for help.
Transcribed Image Text:An analytical chemist is titrating 205.8 mL of a 0.0910 M solution of propylamine \((\text{C}_3\text{H}_7\text{NH}_2)\) with a 0.1800 M solution of \(\text{HNO}_3\). The \(pK_b\) of propylamine is 3.46. Calculate the pH of the base solution after the chemist has added 110.6 mL of the \(\text{HNO}_3\) solution to it. *Note for advanced students:* you may assume the final volume equals the initial volume of the solution plus the volume of \(\text{HNO}_3\) solution added. Round your answer to 2 decimal places. --- \[ \text{pH} = \boxed{} \] Below the text, there are buttons with an 'X' for clearing, a circular arrow for resetting, and a question mark for help.
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