A 100.0 mL solution containing 0.790 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.284 M KOH. Calculate the pH of the solution after the addition of 48.0 mL of the KOH solution. Maleic acid has pK, values of 1.92 and 6.27. pH %D At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H,M, HM, and M2-, which represent the fully protonated, intermediate, and fully deprotonated forms, respectively.
A 100.0 mL solution containing 0.790 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.284 M KOH. Calculate the pH of the solution after the addition of 48.0 mL of the KOH solution. Maleic acid has pK, values of 1.92 and 6.27. pH %D At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H,M, HM, and M2-, which represent the fully protonated, intermediate, and fully deprotonated forms, respectively.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Title: Calculating the pH of a Maleic Acid Solution during Titration**
A 100.0 mL solution containing 0.790 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.284 M KOH. Calculate the pH of the solution after the addition of 48.0 mL of the KOH solution. Maleic acid has \( pK_a \) values of 1.92 and 6.27.
\[ \text{pH} = \]
---
**Concentration of Maleic Acid Forms at Equilibrium**
At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as \( H_2M \), \( HM^- \), and \( M^{2-} \), which represent the fully protonated, intermediate, and fully deprotonated forms, respectively.
\[ [M^{2-}] = \quad \text{M} \]
\[ [HM^-] = \quad \text{M} \]
\[ [H_2M] = \quad \text{M} \]
**Note**: Use the provided tools for \(\times10^{y}\) for adjusting concentration scales.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45d57c72-fda0-4c9d-b683-c1e77ae3201f%2F79ac8c1c-3e01-4b94-a2d5-4a30d9a145f1%2Flgtz9qj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Calculating the pH of a Maleic Acid Solution during Titration**
A 100.0 mL solution containing 0.790 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.284 M KOH. Calculate the pH of the solution after the addition of 48.0 mL of the KOH solution. Maleic acid has \( pK_a \) values of 1.92 and 6.27.
\[ \text{pH} = \]
---
**Concentration of Maleic Acid Forms at Equilibrium**
At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as \( H_2M \), \( HM^- \), and \( M^{2-} \), which represent the fully protonated, intermediate, and fully deprotonated forms, respectively.
\[ [M^{2-}] = \quad \text{M} \]
\[ [HM^-] = \quad \text{M} \]
\[ [H_2M] = \quad \text{M} \]
**Note**: Use the provided tools for \(\times10^{y}\) for adjusting concentration scales.
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