A 100.0 mL solution containing 0.797 g of maleic acid (MW = 116.072 g/mol) is titrated with 0.280 M KOH. Calculate %3D the pH of the solution after the addition of 49.0 mL of the KOH solution. Maleic acid has pk, values of 1.92 and 6.27. pH = At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H, M, HM, and M2", which represent the fully protonated, intermediate, and fully deprotonated forms, respectively. [M²-] = %3D M.

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A 100.0 mL solution containing 0.797 g of maleic acid (MW
116.072 g/mol) is titrated with 0.280 M KOH. Calculate
the pH of the solution after the addition of 49.0 mL of the KOH solution. Maleic acid has pK, values of 1.92 and 6.27.
pH =
At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic
acid are abbreviated as H, M, HM, and M2, which represent the fully protonated, intermediate, and fully deprotonated
forms, respectively.
[M²-] =
M.
[HM | =
%3!
[H, M| =
%3D
Transcribed Image Text:A 100.0 mL solution containing 0.797 g of maleic acid (MW 116.072 g/mol) is titrated with 0.280 M KOH. Calculate the pH of the solution after the addition of 49.0 mL of the KOH solution. Maleic acid has pK, values of 1.92 and 6.27. pH = At this pH, calculate the concentration of each form of maleic acid in the solution at equilibrium. The three forms of maleic acid are abbreviated as H, M, HM, and M2, which represent the fully protonated, intermediate, and fully deprotonated forms, respectively. [M²-] = M. [HM | = %3! [H, M| = %3D
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