A bracket is supported by means of 4 rivets of the same size. Design the diameter of the rivet if C, (tensile ultimate stress) for the rivet material is 560MPA. Which of the rivet has max resistance? 20N 20kN 30 nm s0 mm 30 mm 1.

A bracket is supported by means of 4 rivets of the same size. Design the diameter of the rivet if C, (tensile ultimate stress) for the rivet material is 560MPA. Which of the rivet has max resistance? 20N 20kN 30 nm s0 mm 30 mm 1.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: The hard copper containing solder (L-Cu) connection in Figure 4 is designed to be forced with a…

A: GivenF=18000Nb=30mm

Q: A steel rod with cross-sectional area of 150mm² is stretched between two fixed points. The tensile…

A: Given Variables are

Q: The axial stress on the cross-section of the aluminum rod between A and C is ___ ksi. b). The…

Q: 4.Steel strips , stretched with a force of F = 4,8kN, are fastened with 3 bolts. Materials steel…

Q: The figureshows a copper rod that is placed in an aluminum tube. The rod is 0.005 in. longer than…

A: Allowable stress values should be in Psi not ksi . It seems impractical for this problem.

Q: QUESTION 7 The bar of length 2m has a 60 mm x 6Omm square cross-section with a central hole of 25 mm…

Q: A 400 ft long elevator cable (diameter of 1 inch) is made of 4130 steel with a yield strength of 120…

Q: hollow connecting rod has an inner diameter of 26.25 mm and is subjected to an axial tensile load of…

Q: The acrylic plastic rod is 200 mm long and 15 mm in diameter. If an axial load of 300 N is applied…

A: Stress: When a component or a part is subjected to any external force, a resisting force will be…

Q: (2) A composite member is made of a hollow brass cylinder (E 105 GPa, v= 0.32, and a = interference…

Q: A load of P = 5086 N is acting on member AC. The length of AC is d = 499 mm. The cross-sectional…

A: Load, P= 5086 N Length of the rod AC, d= 499 mm Cross sectional area of AB, AAB= 525 mm2 Cross…

Q: Question Three: Derive expressions that shows 1) Relationship between modulus of elasticity and…

Q: Bearing plate P 0.005 in. 10 in. · Copper -Aluminum

A: here, first guess that max. strees is 10 kis. now if that stress copper is also safe (stress< 20)…

Q: 100 mm 300 mm 100 mm 400 N 400 N B 250 mm A 150 mm -500 mm- 4) If member ABC supports the shown…

Q: A 5⁄8-inch-thick tension member is connected to two 1⁄4-inch splice plates, as shown in Figure The…

A: Bolts are in double shear ϕrn=24.9 kips/bolt {from the manual table 7-1} The required strength…

Q: find shear and Binding monont dkagr 5KN/m 3m 5m ThT 3m

Q: The steel bar has the dimensions shown. (Figure 1) Figure 30 mm 24 mm 20 mm o k 60 mm - 15 mm 1 of 1…

Q: 1-A steel rod having a cross-sectional area of 300 mm2 and is 10 m long .The rod is loading by…

A: The given data are: A=300 mm2=300×10-6 m2L=10 mF=30 kN=30×103 NΔL=5 mm=0.005 m Here, A denotes the…

Q: The rigid pipe is supported by a pin at A and an A-36 steel guy wire BD. Figure 4 ft 3 f 1 of 1 >…

Q: 300lb -800lb 30 30 -200lb 600lb FORCE Ibs F= F.Cos(e) F = F.Sin(e)

Q: The figure shows a roof truss and the detail of the riveted connection at joint B. Using allowable…

A: Given data:τ=70 MPaσb=140MPaABC=864 mm2ABE=1780 mm2for shearing n= 5 rivetsfor bearing n=7 rivets

Q: The figureshows a copper rod that is placed in an aluminum tube. The rod is 0.005 in. longer than…

A: GivenAc=2.78 in2Aal=3.28in2Ec=17013025 ksiEal=10072240…

Q: Hard drawn copper rivets are u

A: Answer: d= 0.36in

Q: 6. The plastic sheet, 1/2 in. thick, is bonded to the pin-jointed steel frame. Determine the…

A: GIVEN DATA- G=70*10^3 psi Thickness t=1/2in we have to find value of force P

Q: The lap joint shown is fastened by four 314" dia. bolts. Assume the applied load is uniformly…

Q: If load P = 20.3 kips, determine the normal force in bar (1). D A 6 ft 43.8 kips 31.0 kips 33.8 kips…

Q: etermine the equivalent stiffness constant

A: situation is something like this 1Keq = 1Kcantilever+1.5 +1KBar

Q: The lap joint carries an P axial load of P - 50 kN. It is connected by 3-18 mm 150 mm 20 mm 20 mm…

A: As given question Load =50 kn T=20mm n=3 Dia=18mm We have to find shear stress, bearing stress and…

Q: Q1. A bracket, as shown in Fig. is supported by 5 bolts, two at the bottom and three above.…

A: To find: The size of bolts. Given: The factor of safety is FOS=2. The number of bolts n=5. The yield…

Q: Click to see additional instructions Calculate the minimum Safety Factor if the radius r= 5mm and M=…

Q: The figureshows a copper rod that is placed in an aluminum tube. The rod is 0.005 in. Ionger than…

Q: Consider the schematic of a riveted lap join subjected to tensile load F, as shown below. Le d be…

A: TO determine the minimum value for the thickness of the plates.

Q: At the proportional limit, a 20-mm-thick x 75-mm-wide bar elongates 7.2 mm under an axial load of…

A: Given : t = 20mm w = 75 mm change in length (elongation) δL = 7.2 mm P = 470 kN = 470000 N L = 1.6…

Q: The connection shown consist of five steel plates joined by a steel bolt with a diameter of 6 mm.…

A: The given information in the problem is shown in the following attached image:

Q: Question One: Derive expressions for determining the change in length for the following bodies P. b.…

Concept explainers

Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

A bracket is supported by means of 4 rivets of the same size. Design the
diameter of the rivet if C, (tensile ultimate stress) for the rivet material is
560MPA. Which of the rivet has max resistance?
20N
20kN
30 nm
so nm
30 mm
1.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1 Given Data

VIEW

Step 2 Calculation

VIEW

Step 3 Calculation

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Types of Properties of Engineering Materials

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

مقاومة المواد
Q2: A spacer is turned from Aluminum alloy with elasticity modulus of 78 GN/m?. The spacer has a diameter of 28 mm and a length of 245 mm. both measurements being made at 20°C. The temperature of the spacer is then increased to 100 °C, the natural expansion being entirely prevented. Taking the coefficient of linear expansion to be 18 x 106 /0C. Determine the compressive load on the spacer. A - 62.63 kN B - 67.12 kN C - 69.16 kN D - 71.82 kN
0.1 mm Сорper Aluminum -100 mm 200 mm The two circularrod segments, one of aluminum and the other of copper, are fixed to the rigid walls such that there is a gap of 0.1 mm between them when T,= 15°C. Each rod has a diameterof 30 mm, aF 23x106°C*1, a= 17×106°C!, Eg= 70 GPa, and E = 126 GPa. cu Determine: 1) The temperature required in order to just close the gap. 2) The average normalstress in each rod when T,= 85°C. 3) The displacementof each rod if T3= 85°C.
A square bar subjected to a tensile load of 100kN having a gauge length of 200mm extends to a length of 0.19mm . Given the tensile strength as 200 MPa , determine ( 1 ) Side of the bar ( express in mm ) Final length ( express in mm ) Modulus of elasticity ( express )
A stepped circular bar having diameters 20 mm, 15: mm and 10 mm over axial lengths of 100 mm, 80mm and 60mm is subjected to an axial tensile force of 5 KN. If E= 100 x 103 N/mm2 and 1/m = 0.32 for the material of bar, determine total change in length and change in each diameter.
Q 2: A circular rod of 15 mm diameter and 120 mm length, is subjected to 2.5 RN tensile load if the diameter become 12 mm find 1. True stress. 2. The length of the rod after deformation.
Hertz contact theory can be used to determine the stresses due to contact between two spheres, which can be used approximate frictionless contact between the patellar and femoral components of a total knee replacement. Part a) Show on a sketch how the stresses at the surface vary from the centre of contact to the edge of contact. Part b) Make a sketch of an infinitesimal element of material at the centre of contact that shows the stress components. Identify the maximum principal stress, and write an expression for the maximum shear stress. Part c) Sketch a graph that shows how the maximum contact pressure varies with load and in a sentence explain why the curve has the shape it does.
Parvinbhai
Tyx 3MP 8MPd 45 2MPA Determine the two principal stresses in MPd
kindly solve this please, thank you
Answer question Q1
Required information Two cylindrical rods, one of steel and the other of brass, are joined at C and restrained by rigid supports at A and E. Given: P₁ = 65 kN and P2 = 40 kN. Take Es = 200 GPa and Eb = 105 GPa. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. -180- Dimensions in mum Steel B 120- P₁ 40-mm diam. 100 100 DI C Brass 30-mm diam. Determine the reactions at A and E. The reaction at A is The reaction at Eis P2 E KN (Click to select) ✓ KN (Click to select)