A block, whose mass is 0.560 kg, is attached to a spring with a force constant of 132 N/m. The block rests upon a frictionless, horizontal surface (shown in the figure below). (A block labeled m is attached to the right end of a horizontal spring, and the left end of the spring is attached to a wall. The spring is stretched horizontally such that the block is displaced by a distance A to the right of its equilibrium position.)   The block is pulled to the right a distance A = 0.140 m from its equilibrium position (the vertical dashed line) and held motionless. The block is then released from rest.   (a) At the instant of release, what is the magnitude of the spring force (in N) acting upon the block?  N   (b) At that very instant, what is the magnitude of the block's acceleration (in m/s2)?  m/s2   (c) In what direction does the acceleration vector point at the instant of release?

Q: To measure the static friction coefficient betwee

A: Given: Mass of the block is m=4.93kg Spring constant K=521 N/m compression x=0.0524m

Q: A 0.281-kg block resting on a frictionless, horizontal surface is attached to a spring having force…

A:

Q: A block of mass 0.75 kg slides on a rough horizontal tabletop. It hits a spring and compresses it…

A: The given values are, m=0.75 kgx=5.7 cm=0.057 mk=100 N/mμk=0.25

Q: Under some circumstances when two parallel springs, with constants k1 and k2, support a single mass,…

A: Given data :  Weighting W = 20 lb  Spring elongation  x1  = 8 inches  x2 = 6 inches  Downward…

Q: A spring with a spring constant of 500 N/m is used to propel a 0.45-kg mass up an inclined plane.…

A:

Q: A wooden block with mass 1.85 kg is placed against a compressed spring at the bottom of a slope…

A: Part A. The distance between point A and B is d=7.55 m. So, according to the given conditions, the…

Q: A spring lies on a horizontal table, and the left end of the spring is attached to a wall. The other…

A: The spring can be stretched up to a distance of 0.073 m.Explanation:

Q: 0.25 kg mass is held against a compressed spring with a spring constant of 2,658 N/m. The mass is…

A:

Q: A 0.26 kg mass is held at rest against a compressed spring with a spring constant of 191 N/m. When…

A: Mass, m = 0.26 kgSpring constant, k = 191 N/mSpeed of mass, v = 6.9 m/s

Q: Hooke's law describes a certain light spring of unstretched length 37.0 cm. When one end is attached…

A:

Q: Hooke's law describes a certain light spring of unstretched length 38.0 cm. When one end is attached…

A: Given data: Unstretched length, L1=38.0 cm Length of the spring, L2=41.50 cm Mass of the object,…

Q: A spring 1.50 m long with force constant 471 N/m is hung from the ceiling of an elevator, and a…

A: Given data, Mass m=14.1 kg Spring Constant k=471 N/m Acceleration a=1.84 m/s2

Q: A spring has been attached at the bottom of the frictionless surface which has angle of 30 degree…

A:

Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 590 N/m as shown in the…

A: Given Data: Mass of the block (m) = 2.00 kg.Distance (x) = 4.05 cm = 4.05×10-2 m.Force constant (k)…

Q: A 0.87 kg block on a connected to a spring (whose spring constant is 3.80 N/m). The horizontal…

A:

Q: A block of mass m = 3.08 kg is attached to a spring that is F (N) resting on a horizontal,…

A:

Q: A 10.0 kg block is released from point A in the Figure below. The track is friction-less except for…

A:

Q: s law describes a certain light spring of unstretched length 30.0 cm. When one end is attached to…

A: We know that force and displacement is given by  F=kx  At equilibrium kx=mg  a) k=mgx=…

Q: A 1.10-kg object slides to the right on a surface having a coefficient of kinetic friction 0.250…

A:

Q: A spring is attached to an inclined plane as shown in the figure. A block of mass m is placed on the…

A: Mass = m Distance = d Initial speed = v Incline angle = θ The surface is friction-less.  Let the…

Q: of k = 700 N/m. A block of mass m = 1.10 kg is attached to the spring and rests on a frictionless,…

A:

Q: 0.19 kg mass is held at rest against a compressed spring with a spring constant of 103 N/m. When…

A: mass (m) =0.19 kgSpring constant (k) = 103 N/m speed when block leaves the contact with spring (vo)…

Q: A 5 kg block is attached to a spring of constant k = 2400 N/m. The coefficient of friction between…

A: We are given spring constant and mass of block. We find the friction force first. We then find the…

Q: A 3.00 kgkg block on a horizontal floor is attached to a horizontal spring that is initially…

A: Given value--- mass = 3 kg. compressed length = 0.036 m. force constant = 845 N/m. coefficient of…

Q: A 0.28 kg mass is held against a compressed spring with a spring constant of 2,446 N/m. The mass is…

A:

Q: 64 ing on a horizontal, frictionless table. The block is pushed 5- o the spring, compressing it by…

A:

Q: A horizontal spring attached to a wall has a force constant of k = 780 N/m. A block of mass m = 1.90…

A:

Q: need help with finding the last part.  A moving 1.70 kg block collides with a horizontal spring…

A:

Q: a 2 kg weight is fasten to a spring on an inclined plane. It has a spring constant of 20 N/m.  When…

A: Given information: The mass of the block (M) = 2.0 kg The spring constant of the spring (k) = 20 N/m…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.