A 5 kg block is attached to a spring of constant k = 2400 N/m. The coefficient of friction between the block and the ground is 0.4. Under its initial condition, a force F is applied to the block until the restoring force of the spring reaches 100 N. To reach its final condition, the applied force F is removed. Then, the block moves and the spring returns to its unstretched position. Use 9.81m/s^2 for the gravity. a) Using the formula Fspring=kx, determine the distance in meters of the block from its unstretched position until it has a restoring force of 100N. b)Determine the work done by friction in Joules from the initial position (stretched) to its final position (unstretched). c)If the total work done on the system is 1.2658 J, determine the final velocity of the block (by relating work and kinetic energy)

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A 5 kg block is attached to a spring of constant k = 2400 N/m. The coefficient of friction between the block and the ground is 0.4. Under its initial condition, a force F is applied to the block until the restoring force of the spring reaches 100 N. To reach its final condition, the applied force F is removed. Then, the block moves and the spring returns to its unstretched position. Use 9.81m/s^2 for the gravity.

a) Using the formula Fspring=kx, determine the distance in meters of the block from its unstretched position until it has a restoring force of 100N.

b)Determine the work done by friction in Joules from the initial position (stretched) to its final position (unstretched).

c)If the total work done on the system is 1.2658 J, determine the final velocity of the block (by relating work and kinetic energy)

Espring = 100N
k=2400 N/m
ww
5 kg
F
Transcribed Image Text:Espring = 100N k=2400 N/m ww 5 kg F
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