A 1120-kg car is being driven up a 7.03 ° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of 490 N. A force F is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight W and the normal force FN directed perpendicular to the road surface. The length of the road up the hill is 281 m. What should be the magnitude of F, in Newtons, so that the net work done by all the forces acting on the car is 188 kJ?
A 1120-kg car is being driven up a 7.03 ° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of 490 N. A force F is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight W and the normal force FN directed perpendicular to the road surface. The length of the road up the hill is 281 m. What should be the magnitude of F, in Newtons, so that the net work done by all the forces acting on the car is 188 kJ?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A 1120-kg car is being driven up a 7.03 ° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of 490 N. A force F is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight W and the normal force FN directed perpendicular to the road surface. The length of the road up the hill is 281 m. What should be the magnitude of F, in Newtons, so that the net work done by all the forces acting on the car is 188 kJ?
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