Please explain the steps to find the answer, which equation you are using and why you are using it. Also a small reflection about the problem. Thanks. JC-Challenge 2) Electron Beam on Beam StopA beam of 2.14 × 10' electons per second moving at a speed of 0.813c strikes ablock of copper that is used as a beam stop. The copper black is a cute measuring 2.54 cm on edge.What is the temperature increase of the block after exactly one hour?

Given Electron beam = 2.14×1011 electron/s Speed of electron ve =…

A beam of 2.14 × 10'' electons per second moving at a speed of 0.813c strikes a block of copper that is used as a beam stop. The copper black is a cute measuring 2.54 cm on edge. What is the temperature increase of the block after exactly one hour?

A beam of 2.14 × 10'' electons per second moving at a speed of 0.813c strikes a block of copper that is used as a beam stop. The copper black is a cute measuring 2.54 cm on edge. What is the temperature increase of the block after exactly one hour?

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Question

Please explain the steps to find the answer, which equation you are using and why you are using it. Also a small reflection about the problem. Thanks.

JC-Challenge 2) Electron Beam on Beam Stop
A beam of 2.14 × 10' electons per second moving at a speed of 0.813c strikes a
block of copper that is used as a beam stop. The copper black is a cute measuring 2.54 cm on edge.
What is the temperature increase of the block after exactly one hour?

Expert Solution

Step 1

Given

Electron beam = $2.14 \times 10^{11} electron / s$

Speed of electron $(v_{e})$ = 0.813 c $(∵ c = 3 \times 10^{8} m / s)$

Mass of electron $(m_{e})$ = $9.109 \times 10^{- 31} kilograms$

Volume of copper $(v_{c})$ = 2.54 cm

Density of the copper $(ρ_{c})$ = 8.96 $g / {cm}^{3}$

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