The rectangular solid is made of two blocks of different materials: - The top block (medium 1) has thickness t1 = 1.37 cm and index of refraction n1 = 1.66 - The bottom block (medium 2) has thickness t2 = 8.5 cm and index of refraction n2 = 2.28 A ray of light traveling in air (n = 1.00) strikes the top of the solid at angle of incidence 0, = 28.3°. Find D, the horizontal displacement of the light ray (the horizontal distance from the point at which the light enters the top block to the point at which the light leaves the block), in cm. Assume: as in the diagram, the ray does not reach the end of the blocks.

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### Refraction of Light through a Double Medium

**Diagram 1: Light Refraction through Layered Media**

This diagram illustrates the refraction of light as it travels through two different media, denoted as \( n_1 \) and \( n_2 \).

- **Medium Description:**
  - **Air**: The light initially travels through this medium before entering the first layer.
  - **\( n_1 \)**: The first medium layer with a refractive index of \( n_1 \).
  - **\( n_2 \)**: The second medium layer with a refractive index of \( n_2 \).

- **Path of Light:**
  - The light enters from the air and hits the surface of medium \( n_1 \) at an angle labeled \( \theta_0 \).
  - Upon entering \( n_1 \), the light refracts, bending towards the normal line due to the change in speed as it moves into a denser medium.
  - As the light travels through \( n_1 \) and enters \( n_2 \), it again changes direction due to another change in the refractive index.

- **Additional Annotation:**
  - \( D \) refers to the horizontal distance covered by the light path in the \( n_1 \) medium before it hits \( n_2 \).

This setup helps to demonstrate the principle of refraction, governed by Snell's Law, which predicts the path of light in materials of varying optical densities.
Transcribed Image Text:### Refraction of Light through a Double Medium **Diagram 1: Light Refraction through Layered Media** This diagram illustrates the refraction of light as it travels through two different media, denoted as \( n_1 \) and \( n_2 \). - **Medium Description:** - **Air**: The light initially travels through this medium before entering the first layer. - **\( n_1 \)**: The first medium layer with a refractive index of \( n_1 \). - **\( n_2 \)**: The second medium layer with a refractive index of \( n_2 \). - **Path of Light:** - The light enters from the air and hits the surface of medium \( n_1 \) at an angle labeled \( \theta_0 \). - Upon entering \( n_1 \), the light refracts, bending towards the normal line due to the change in speed as it moves into a denser medium. - As the light travels through \( n_1 \) and enters \( n_2 \), it again changes direction due to another change in the refractive index. - **Additional Annotation:** - \( D \) refers to the horizontal distance covered by the light path in the \( n_1 \) medium before it hits \( n_2 \). This setup helps to demonstrate the principle of refraction, governed by Snell's Law, which predicts the path of light in materials of varying optical densities.
**Problem Description:**

Refer to diagram 1.

The rectangular solid is made of two blocks of different materials:
- **Top block (medium 1):** Thickness \( t_1 = 1.37 \) cm and index of refraction \( n_1 = 1.66 \)
- **Bottom block (medium 2):** Thickness \( t_2 = 8.5 \) cm and index of refraction \( n_2 = 2.28 \)

A ray of light traveling in air \( (n = 1.00) \) strikes the top of the solid at an angle of incidence \( \theta_0 = 28.3^\circ \). Find \( D \), the horizontal displacement of the light ray (the horizontal distance from the point at which the light enters the top block to the point at which the light leaves the block), in cm. Assume: as in the diagram, the ray does not reach the end of the blocks.
Transcribed Image Text:**Problem Description:** Refer to diagram 1. The rectangular solid is made of two blocks of different materials: - **Top block (medium 1):** Thickness \( t_1 = 1.37 \) cm and index of refraction \( n_1 = 1.66 \) - **Bottom block (medium 2):** Thickness \( t_2 = 8.5 \) cm and index of refraction \( n_2 = 2.28 \) A ray of light traveling in air \( (n = 1.00) \) strikes the top of the solid at an angle of incidence \( \theta_0 = 28.3^\circ \). Find \( D \), the horizontal displacement of the light ray (the horizontal distance from the point at which the light enters the top block to the point at which the light leaves the block), in cm. Assume: as in the diagram, the ray does not reach the end of the blocks.
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