A BAn ABCOF LeuaTHPARTS OF E@uAL LENGTH. SEGMENT Aß HASCONSISTSOF2ADIAMETCR d,= 100 mmAND SEGMENT BCHAs A O1A METER d, = 60mm. Born SeGMENTSHAve ALENGTH Lb =600mm.d= 24 mmA LONGITUNAL HOLE OF DIAMETCRIsDRILL THRoUGH SEGMEUr ABFOr ONE HALFLENGTH (44= 300mm). The Bar isE=4G Pa.OF ITSMADE OF PLASTIC WITHFiNo THERELATIUE ToRELATIVE DOisPLACEM ENT of Powr CPoiNt A. (Sch)didz110KN110KNABC

Given, Compressive Load P = -110 kN Diameter of AB d1 = 100 mm Diameter of BC d2 = 60 mm Hole…

Answered: A BAn ABC OF LeuaTH PARTS OF E@uAL…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

A BAn ABC
OF LeuaTH
PARTS OF E@uAL LENGTH. SEGMENT Aß HAS
CONSISTS
OF
2
A
DIAMETCR d,= 100 mm
AND SEGMENT BC
HAs A O1A METER d, = 60mm. Born SeGMENTS
HAve A
LENGTH Lb =600mm.
d= 24 mm
A LONGITUNAL HOLE OF DIAMETCR
Is
DRILL THRoUGH SEGMEUr AB
FOr ONE HALF
LENGTH (44= 300mm). The Bar is
E=4G Pa.
OF ITS
MADE OF PLASTIC WITH
FiNo THE
RELATIUE To
RELATIVE DOisPLACEM ENT of Powr C
PoiNt A. (Sch)
di
dz
110KN
110KN
A
B
C

Expert Solution

Step 1

Given,

Compressive Load P = -110 kN

Diameter of AB d₁ = 100 mm

Diameter of BC d₂ = 60 mm

Hole diameter in AB d = 24 mm

E = 4 GPa = 4000 MPa

Step 2

Suppose a point D as shown above.

Length of section AD L₁ = 300 mm

Length of section DB L₂ = 300 mm

Length of section BC L₃ = 600 mm

Step 3

Net area of section

$A r e a A D, A_{1} = \frac{π}{4} (d_{1}^{2} - d^{2}) m m^{2} A_{1} = \frac{π}{4} ({(100)}^{2} - (24^{2})) m m^{2} A_{1} = 7401.59 m m^{2} A r e a D B, A_{2} = \frac{π}{4} d_{1}^{2} m m^{2} A_{2} = \frac{π}{4} {(100)}^{2} m m^{2} A_{2} = 7853.98 m m^{2} A r e a B C, A_{3} = \frac{π}{4} d_{2}^{2} m m^{2} A_{3} = \frac{π}{4} {(60)}^{2} m m^{2} A_{3} = 2827.43 m m^{2}$

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