The axial assembly consists of a solid 1.03-in.-diameter aluminum alloy [E = 9700 ksi, v = 0.24, a = 13.3 x 10-6/°F] rod (1) and a solid 1.45-in.-diameter bronze [E = 14100 ksi, v=0.12, a = 8.5 x 10-6/°F] rod (2). Assume L₁=12 in., L2=28 in. If the supports at A and C are rigid and the assembly is stress free at 19°F, determine: (a) the normal stresses 01, 02 in both rods at 144°F (positive if tensile, negative if compressive). (b) the displacement ug of flange B (positive if to the right, negative to the left). (c) the change in diameter Ad, of the aluminum rod. Answers: (a) o₁ = (b) UB= (c) Ad₁ = (1) L₁ i 22.197 -0.0075 i B 0.00041 in. L2 (2) ksi, O₂ = i in. 11.199 ksi

The axial assembly consists of a solid 1.03-in.-diameter aluminum alloy [E = 9700 ksi, v = 0.24, a = 13.3 x 10-6/°F] rod (1) and a solid 1.45-in.-diameter bronze [E = 14100 ksi, v=0.12, a = 8.5 x 10-6/°F] rod (2). Assume L₁=12 in., L2=28 in. If the supports at A and C are rigid and the assembly is stress free at 19°F, determine: (a) the normal stresses 01, 02 in both rods at 144°F (positive if tensile, negative if compressive). (b) the displacement ug of flange B (positive if to the right, negative to the left). (c) the change in diameter Ad, of the aluminum rod. Answers: (a) o₁ = (b) UB= (c) Ad₁ = (1) L₁ i 22.197 -0.0075 i B 0.00041 in. L2 (2) ksi, O₂ = i in. 11.199 ksi

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Need help with part A and C and the answers ive calculated are incorrect. Part B is done correctly.

=
The axial assembly consists of a solid 1.03-in.-diameter aluminum alloy [E = 9700 ksi, v = 0.24, a 13.3 x 10-6/°F] rod (1) and a
solid 1.45-in.-diameter bronze [E = 14100 ksi, v = 0.12, a = 8.5 x 10-6/°F] rod (2). Assume L₁-12 in., L₂=28 in. If the supports at A and
Care rigid and the assembly is stress free at 19°F, determine:
(a) the normal stresses 01, 02 in both rods at 144°F (positive if tensile, negative if compressive).
(b) the displacement up of flange B (positive if to the right, negative to the left).
(c) the change in diameter Ad₁ of the aluminum rod.
Answers:
(a) 01
(b) UB=
(c) Ad₁
=
(1)
L₁
i
22.197
-0.0075
B
0.00041
in.
L2
ksi, 02 =
in.
C
11.199
ksi

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