A ball of mass 500-gram is moving in a horizontal circular path of radius 15cm. If the time for 20 complete cycle is 10 seconds, find the centripetal acceleration and centripetal force for the mass. If the uncertainties in mass, radius and time period are 0.1 gram, 0.01 cm and 0.1 sec respectively, find the uncertainties in centripetal acceleration and centripetal force.

A ball of mass 500-gram is moving in a horizontal circular path of radius 15cm. If the time for 20 complete cycle is 10 seconds, find the centripetal acceleration and centripetal force for the mass. If the uncertainties in mass, radius and time period are 0.1 gram, 0.01 cm and 0.1 sec respectively, find the uncertainties in centripetal acceleration and centripetal force.

Similar questions

If you took the Earth and reduced its radius to one fourth its current size, what would the escape velocity from the Earth be?
When the Moon is directly overhead at sunset, the force by Earth on the Moon, FEM, is essentially at 90° to the force by the Sun on the Moon, FSM, as shown below. FEM=1.98×10^20N and FSM=4.36×10^20N, all other forces on the Moon are negligible, and the mass of the Moon is 7.35×10^22kg. 1. Write an expression for the magnitude of the acceleration of the Moon. 2. What is the acceleration of the Moon in m/s^2?
) One of the moors of Jupiter, named an orbital radius of 10 4.22 * 10 ^ 8 a period of 1.77 days. Assuming the orbitis circular, calculate the inass of Jupiter. (b) largest moon of Jupiter, named Ganymede, has an orbital radius of 1.07 * 10 ^ 9 m a period of 7.16 daysCalculate the mass of Jupiter from this data ) your results to parts (b) consistent ? Yes No Explain
A mood of a mass m and raduis a is orbiting a planet of mass M and if radius b at a distance d (center to center) in a circular orbit. Derive an expression for the speed of the mood v in terms of M,d and the gravitational constant G.
The class I'm taking is physics for scientists and engineers! I am completely stuck. Need help. I have attached the problem. Please view both attachments before answering. Please write step-by-step solution so I can fully understand.
We will use differential equations to model the orbits and locations of Earth, Mars, and the spacecraft using Newton’s two laws mentioned above. Newton’s second law of motion in vector form is: F^→=ma^→ (1) where F^→ is the force vector in N (Newtons), and a^→ is the acceleration vector in m/s^2,and m is the mass in kg. Newton’s law of gravitation in vector form is: F^→=GMm/lr^→l*r^→/lr^→l where G=6.67x10^-11 m^3/s^2*kg is the universal gravitational constant, M is the mass of the larger object (the Sun), and is 2x10^30 kg, and m is the mass the smaller one (the planets or the spacecraft). The vector r^→ is the vector connecting the Sun to the orbiting objects. Step one ) The motion force in Equation(1), and the gravitational force in Equation(2) are equal. Equate the right hand sides of equations (1) and (2), and cancel the common factor on the left and right sides. Answer: f^→=ma^→ f=Gmm/lr^→l^2 a^→=Gmm/lr^→l^2 x r^→/lr^→l r^→=r^→/lr^→l * Gmm Could you please…
Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is v| = 225 km/s and the orbital period of each is 11.6 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 x 1030 kg.) M XCM M Part 1 of 3 - Conceptualize From the given data, it is difficult to estimate a reasonable answer to this problem without working through the details and actually solving it. A reasonable guess might be that each star has a mass equal to or slightly larger than our Sun because fourteen days is short compared to the periods of all the Sun's planets. Part 2 of 3 - Categorize The only force acting on each star is the central gravitational force of attraction which results in a centripetal acceleration. When we solve Newton's second law, we can find the unknown mass in terms of the variables…
We would like to be able to make meaningful interpretations of variations in the acceleration due to gravity, g, as small as 0.1 mgal. How accurate must our knowledge of the latitude of our gravity stations be? (A “gravity station" is just a location at which you make a gravity measurement.) You can assume your latitude is 45°.
Please solve
Needs Complete solution with 100 % accuracy.
How much energy is required to move a satellite of mass 1000 kg from the surface of the Earth to an altitude 3 times the radius of the Earth? Compute the energy in joules.
A 750-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. 1768.95 × Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (b) Find the period of its revolution. 12.576 Your response differs from the correct answer by more than 100%. h (c) Find the gravitational force acting on it. 114.11 × Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N