a An 82-kg skater is pushed on a frictionless surface through a straight line displacement of = (13.2m) + (18.9m)ŷ by a force F = (182N) + (121N). How much work does the force do on the skater during this displacement? i J
a An 82-kg skater is pushed on a frictionless surface through a straight line displacement of = (13.2m) + (18.9m)ŷ by a force F = (182N) + (121N). How much work does the force do on the skater during this displacement? i J
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Can you assess my work and tell me if i'm going about this the right way? I didn't utilize mass at all, which is confusing me a bit.
![6.1 Work Done by a Constant Force
An 82-kg skater is pushed on a frictionless surface through a straight line displacement of a = (13.2m) + (18.9m)ỹ by a force
d
(182N) + (121N). How much work does the force do on the skater during this displacement? i
F
J
=
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K](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d4854d9-aadf-4fe0-b1f6-bd622f90aeab%2Ff3fd0975-75cb-4ca7-b700-e18e853be816%2F72gxeol_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6.1 Work Done by a Constant Force
An 82-kg skater is pushed on a frictionless surface through a straight line displacement of a = (13.2m) + (18.9m)ỹ by a force
d
(182N) + (121N). How much work does the force do on the skater during this displacement? i
F
J
=
Save for Later
Submit Answer
K
![6.1
m: 82kg
J =
(13.2m) x + ( 18.9m) ÿ
7² = (182N) = + (121NDY
Find Wo during displacement
W = F
FS
W x = (182N) (13.2m) -
->
2402.4N.H
1
->
Wy = (121N) (18.9m) >>
2286.9 N.M
W² = √√(√2402.4)² + (2286.9) ²
106 673 = √5441525.76 + 5229911.61
W² = 3316.8
pl
22
b
ja
1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d4854d9-aadf-4fe0-b1f6-bd622f90aeab%2Ff3fd0975-75cb-4ca7-b700-e18e853be816%2F8jeul7s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6.1
m: 82kg
J =
(13.2m) x + ( 18.9m) ÿ
7² = (182N) = + (121NDY
Find Wo during displacement
W = F
FS
W x = (182N) (13.2m) -
->
2402.4N.H
1
->
Wy = (121N) (18.9m) >>
2286.9 N.M
W² = √√(√2402.4)² + (2286.9) ²
106 673 = √5441525.76 + 5229911.61
W² = 3316.8
pl
22
b
ja
1
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