d Astronomers define the redshift z of light from a receding astronomical object by the formula Z femit -fobs fobs Here femit is the frequency of the light measured in the frame in which the emitter is at rest and fobs the frequency observed in another frame in which the emitter moves directly away from the observer. = The most distant quasar reported as of 1991 has a redshift z 4.897. With what fraction of the speed of light is this quasar receding from us?

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I rewrote the question to get z=(1+z)v/c, plugged in z and got 0.8603. Is this the correct approach?

d Astronomers define the redshift z of light
from a receding astronomical object by the formula
Z
femit-fobs
fobs
Here femit is the frequency of the light measured in
the frame in which the emitter is at rest and fobs the
frequency observed in another frame in which the
emitter moves directly away from the observer.
The most distant quasar reported as of 1991 has a
redshift z = = 4.897. With what fraction of the speed
of light is this quasar receding from us?
Transcribed Image Text:d Astronomers define the redshift z of light from a receding astronomical object by the formula Z femit-fobs fobs Here femit is the frequency of the light measured in the frame in which the emitter is at rest and fobs the frequency observed in another frame in which the emitter moves directly away from the observer. The most distant quasar reported as of 1991 has a redshift z = = 4.897. With what fraction of the speed of light is this quasar receding from us?
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