(a) A light, rigid rod of length { = 1.00 m joins two particles, with masses m, = 4.00 kg and m, = 3.00 kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod (see figure below). Determine the angular momentum of the system about the origin when the speed of each particle is 4.00 m/s. (Enter the magnitude to at least two decimal places in kg - m2/s.) magnitude 7 Note that the velocity of each particle is perpendicular to the vector giving its position relative to the origin, so the cross product is particularly simple in this case. kg · m/s direction (b) What If? What would be the new angular momentum of the system (in kg - m/s) if each of the masses were instead a solid sphere 15.0 cm in diameter? (Round your answer to at least two decimal places.) 18.641 x kg - m?/s

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**Angular Momentum Analysis**

**(a)** A light, rigid rod of length \( \ell = 1.0 \, \text{m} \) joins two particles with masses \( m_1 = 4.00 \, \text{kg} \) and \( m_2 = 3.00 \, \text{kg} \) at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod. Determine the angular momentum of the system about the origin when the speed of each particle is \( 4.00 \, \text{m/s} \). (Enter the magnitude to at least two decimal places in kg · m²/s.)

- A diagram illustrates a rod with particles \( m_1 \) and \( m_2 \) on either end, rotating counterclockwise around the origin in the xy-plane. The vectors are perpendicular to the line joining the origin to the particles.

1. **Magnitude:** [User Input: Incorrect Example Provided: "7"]

2. **Direction:** [Choice of directions, e.g., -x]

*Note:* The velocity of each particle is perpendicular to the vector giving its position relative to the origin, so the cross product calculation is simplified.

**(b) What If?** 

What would be the new angular momentum of the system (in kg · m²/s) if each of the masses were instead a solid sphere with a diameter of 15.0 cm? (Round your answer to at least two decimal places.)

- **User Input for New Angular Momentum:** [Incorrect Example Provided: "18.641"]

**Explanation:**
The rigid rod system's angular momentum depends on the mass distribution and the velocity of the particles. When analyzing the effect of changing the mass shape to a solid sphere, consider the change in moment of inertia. The input fields and corrective feedback offer insights into precise calculations involving cross products in rotational motion.
Transcribed Image Text:**Angular Momentum Analysis** **(a)** A light, rigid rod of length \( \ell = 1.0 \, \text{m} \) joins two particles with masses \( m_1 = 4.00 \, \text{kg} \) and \( m_2 = 3.00 \, \text{kg} \) at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod. Determine the angular momentum of the system about the origin when the speed of each particle is \( 4.00 \, \text{m/s} \). (Enter the magnitude to at least two decimal places in kg · m²/s.) - A diagram illustrates a rod with particles \( m_1 \) and \( m_2 \) on either end, rotating counterclockwise around the origin in the xy-plane. The vectors are perpendicular to the line joining the origin to the particles. 1. **Magnitude:** [User Input: Incorrect Example Provided: "7"] 2. **Direction:** [Choice of directions, e.g., -x] *Note:* The velocity of each particle is perpendicular to the vector giving its position relative to the origin, so the cross product calculation is simplified. **(b) What If?** What would be the new angular momentum of the system (in kg · m²/s) if each of the masses were instead a solid sphere with a diameter of 15.0 cm? (Round your answer to at least two decimal places.) - **User Input for New Angular Momentum:** [Incorrect Example Provided: "18.641"] **Explanation:** The rigid rod system's angular momentum depends on the mass distribution and the velocity of the particles. When analyzing the effect of changing the mass shape to a solid sphere, consider the change in moment of inertia. The input fields and corrective feedback offer insights into precise calculations involving cross products in rotational motion.
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