(c) By pulling on the rope, one astronaut shortens the distance between them to 5.00 m. What is the new angular momentum of the system? (d) What are the astronauts' new speeds?

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Chapter1: Units, Trigonometry. And Vectors
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I got part (a) of this question but am stuck on the rest:

Two astronauts (figure), each having a mass of 72.0 kg, are connected by a d = 9.0-m rope of negligible mass. They are isolated in space, orbiting their center of mass at speeds of 4.90 m/s. 

a) Treating the astronauts as particles, calculate the magnitude of the angular momentum of the two-astronaut system. (The correct answer to this part is 3175.2 kg*m^2/s)

(b) Calculate the rotational energy of the system.

(c) By pulling on the rope, one astronaut shortens the distance between them to 5.00 m. What is the new angular momentum of the system?

(d) What are the astronauts' new speeds?

(e) What is the new rotational energy of the system?

(f) How much chemical potential energy in the body of the astronaut was converted to mechanical energy in the system when he shortened the rope?

The diagram depicts two astronauts in space performing a tug-of-war with a rope. The astronauts are positioned at either end of the rope. The center of mass, labeled "CM," is marked with a red "X" at the midpoint of the rope. The distance "d" is indicated between one astronaut and the center of mass. Arrows on both sides of the diagram show rotational movement around the center of mass, illustrating balanced forces.
Transcribed Image Text:The diagram depicts two astronauts in space performing a tug-of-war with a rope. The astronauts are positioned at either end of the rope. The center of mass, labeled "CM," is marked with a red "X" at the midpoint of the rope. The distance "d" is indicated between one astronaut and the center of mass. Arrows on both sides of the diagram show rotational movement around the center of mass, illustrating balanced forces.
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