A, A, G та W OEMA= W. sin 0 = m · a · . cos e 2 OEF, = A, = m· a UE MG = - A,. cos 0 + Ay · . L sin 0 = m· a · 2 2 · cos 0 L EMG = - A . cos 0+ Ay · - sin 0 = 0 OF. = A, = 0 OEMA = W . - sin 0 = 0 2 OF, = A, – W = m·a OEMA = W.!. sin 0 = Iç ·a %3D 2 OEF, = A, – W = 0

A, A, G та W OEMA= W. sin 0 = m · a · . cos e 2 OEF, = A, = m· a UE MG = - A,. cos 0 + Ay · . L sin 0 = m· a · 2 2 · cos 0 L EMG = - A . cos 0+ Ay · - sin 0 = 0 OF. = A, = 0 OEMA = W . - sin 0 = 0 2 OF, = A, – W = m·a OEMA = W.!. sin 0 = Iç ·a %3D 2 OEF, = A, – W = 0

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

A,
A,
G
та
W
OEMA= W. sin 0 = m · a ·
. cos e
2
OEF, = A,
= m· a
UE MG = - A,. cos 0 + Ay · .
L
sin 0 = m· a ·
2
2
· cos 0
L
EMG = - A . cos 0+ Ay · - sin 0 = 0
OF. = A, = 0
OEMA = W . - sin 0 = 0
2
OF, = A, – W = m·a
OEMA = W.!. sin 0 = Iç ·a
%3D
2
OEF, = A, – W = 0

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