Homework Help is Here – Start Your Trial Now!
Engineering
Mechanical Engineering
where did the no. 2 come from in the Fdf. Fdf=2Ffgcos63.43

where did the no. 2 come from in the Fdf. Fdf=2Ffgcos63.43

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
See similar textbooks
icon
Related questions
Question

where did the no. 2 come from in the Fdf. Fdf=2Ffgcos63.43

Given STEP1 800lb 600lb 20 20: C 201E 20 400lb て RE ニ 1400 (^) Royx ニ 6oo b (a) Roy)= 80elb(か) Lusing method of joints) DeromPne> FFy, FEG, FRE O FCE (wing method of section)
Transcribed Image Text:Given STEP1 800lb 600lb 20 20: C 201E 20 400lb て RE ニ 1400 (^) Royx ニ 6oo b (a) Roy)= 80elb(か) Lusing method of joints) DeromPne> FFy, FEG, FRE O FCE (wing method of section)
STEPZ Bolution part 9 Drau FBD PL Boo lb 600 Jo 20 20 20 400lb Reニnoo.b 1000 lb Considey jeiw-by O-tan () = 63. 43' R FEG E Fy-0, Ffo sin(63.93)= -800 6343 FFg= m894.465lb -GOoeb FEG Efx-0 FFy6OS63, 43 +FE O=-600 80olb FEG =-600- (-894.465)0s FEG = 6343 200eb Considler jont F EFy-, (FeF ナFFy)sme393こ 63A 63 143 FDF FEF ニ +894.46516 I Fx =0 FDF+ FEplOs63.43= Ffofos63.43 FEP FDF = (Ffn- FEF) tel63.43 FF4=894.465 lb (compresin) FRF= 2 & FFO Cos 63. 43 FEG= 2004 (compressjon) FRE= 900blcompretsion) FDF = 2x (-894. 465-) Col 63.43 FDF800 lb ) methodof section Cconsider lett side of-seution) 400X304 9 FFX20 Rex 1D 1400x 1D 12000 + FCE X20 . FCE = 100 lb(Tensio )
Transcribed Image Text:STEPZ Bolution part 9 Drau FBD PL Boo lb 600 Jo 20 20 20 400lb Reニnoo.b 1000 lb Considey jeiw-by O-tan () = 63. 43' R FEG E Fy-0, Ffo sin(63.93)= -800 6343 FFg= m894.465lb -GOoeb FEG Efx-0 FFy6OS63, 43 +FE O=-600 80olb FEG =-600- (-894.465)0s FEG = 6343 200eb Considler jont F EFy-, (FeF ナFFy)sme393こ 63A 63 143 FDF FEF ニ +894.46516 I Fx =0 FDF+ FEplOs63.43= Ffofos63.43 FEP FDF = (Ffn- FEF) tel63.43 FF4=894.465 lb (compresin) FRF= 2 & FFO Cos 63. 43 FEG= 2004 (compressjon) FRE= 900blcompretsion) FDF = 2x (-894. 465-) Col 63.43 FDF800 lb ) methodof section Cconsider lett side of-seution) 400X304 9 FFX20 Rex 1D 1400x 1D 12000 + FCE X20 . FCE = 100 lb(Tensio )
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Slope and Deflection
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY
SEE MORE TEXTBOOKS