A 853 N magician (note: this is weight, not mass) is freeing himself from some shackles while suspended above a swimming pool filled with alligators. Two ropes are suspending the magician. The left rope makes an angle of 42 above the horizontal and points up and to the left. The right rope makes an angle of 78 above the horizontal and points up and to the right. Calculate the tension in the left rope, in N.

A 853 N magician (note: this is weight, not mass) is freeing himself from some shackles while suspended above a swimming pool filled with alligators. Two ropes are suspending the magician. The left rope makes an angle of 42 above the horizontal and points up and to the left. The right rope makes an angle of 78 above the horizontal and points up and to the right. Calculate the tension in the left rope, in N.

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A bag of cement weighing 525 N hangs in equilibrium from three wires as suggested in the figure below. Two of the wires make angles 0, = 62.0° and 0, = 43.0° with the horizontal. Assuming the system is in equilibrium, find the tensions T,, T,, and T, in the wires. 269.42 T = Consider the net force at the point where the three wires come together. What is the acceleration of this point? N 420.98 Ta = The horizontal component of your T, is not equal to the horizontal component of your T,, so the object would be accelerating horizontally. N T3 525 N T T2 T3 Need Help? Watch It Read It
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A bag of cement weighing 525 N hangs in equilibrium from three wires as suggested in the figure below. Two of the wires make 62.0⁰ and 02 = 43.0° with the horizontal. Assuming the system is in equilibrium, find the tensions T₁, T2, and T3 angles 0₁ 1' in the wires. T₁ = 0 = Consider the net force at the point where the three wires come together. What is the acceleration of this point? N 0.53 X T₂ = The horizontal component of your T₁ is not equal to the horizontal component of your T₂, so the object would be accelerating horizontally. N T3 = 525 N 201 T₁ CEMENT T3 0₂ T₂ Fg
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