A wracking ball is suspended below two cables each at an angle with the horizontal. The left cable has tension T1 and angle 42 degrees with the horizontal. The right cable has tension T2 and angle 26 degrees with the horizontal. The Wracking ball has mass 120 kg. Find the magnitude of tension T1.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
### Problem Description:

A wrecking ball is suspended below two cables, each at an angle with the horizontal. The left cable has tension \( T1 \) and forms an angle \( α \) of 42 degrees with the horizontal. The right cable has tension \( T2 \) and forms an angle \( β \) of 26 degrees with the horizontal. The wrecking ball has a mass of 120 kg.

**Objective:**
Find the magnitude of tension \( T1 \).

### Detailed Diagram Explanation:

The diagram illustrates a rectangular structure from which a wrecking ball is suspended. Two cables attach the wrecking ball to the rectangular structure, one on the left and one on the right. 

- The left cable makes an angle \( \alpha \) of 42 degrees with the horizontal and has a tension represented by \( \overrightarrow{T1} \).
- The right cable makes an angle \( \beta \) of 26 degrees with the horizontal and has a tension represented by \( \overrightarrow{T2} \).

### Key Elements in the Diagram:

1. **Rectangular Structure:**
   - The point of attachment for both cables.

2. **Cables:**
   - Left Cable (\( \overrightarrow{T1} \)) forms an angle \( \alpha \) (42 degrees) with the horizontal.
   - Right Cable (\( \overrightarrow{T2} \)) forms an angle \( \beta \) (26 degrees) with the horizontal.

3. **Wrecking Ball:**
   - Mass of 120 kg.

### Required Calculation:

To find the magnitude of tension \( T1 \):

1. **Identify Forces:** 
   - The gravitational force acting downward on the wrecking ball: \( F_g = m \cdot g \), where \( m \) is 120 kg and \( g \) is the acceleration due to gravity (9.8 m/s²).
   
   \[
   F_g = 120 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 1176 \, \text{N}
   \]

2. **Establish Equilibrium Conditions:** 
   - For horizontal components: \(\sum F_x = T1 \cos(\alpha) - T2 \cos(\beta) = 0\)
   - For vertical components: \(\sum F_y = T
Transcribed Image Text:### Problem Description: A wrecking ball is suspended below two cables, each at an angle with the horizontal. The left cable has tension \( T1 \) and forms an angle \( α \) of 42 degrees with the horizontal. The right cable has tension \( T2 \) and forms an angle \( β \) of 26 degrees with the horizontal. The wrecking ball has a mass of 120 kg. **Objective:** Find the magnitude of tension \( T1 \). ### Detailed Diagram Explanation: The diagram illustrates a rectangular structure from which a wrecking ball is suspended. Two cables attach the wrecking ball to the rectangular structure, one on the left and one on the right. - The left cable makes an angle \( \alpha \) of 42 degrees with the horizontal and has a tension represented by \( \overrightarrow{T1} \). - The right cable makes an angle \( \beta \) of 26 degrees with the horizontal and has a tension represented by \( \overrightarrow{T2} \). ### Key Elements in the Diagram: 1. **Rectangular Structure:** - The point of attachment for both cables. 2. **Cables:** - Left Cable (\( \overrightarrow{T1} \)) forms an angle \( \alpha \) (42 degrees) with the horizontal. - Right Cable (\( \overrightarrow{T2} \)) forms an angle \( \beta \) (26 degrees) with the horizontal. 3. **Wrecking Ball:** - Mass of 120 kg. ### Required Calculation: To find the magnitude of tension \( T1 \): 1. **Identify Forces:** - The gravitational force acting downward on the wrecking ball: \( F_g = m \cdot g \), where \( m \) is 120 kg and \( g \) is the acceleration due to gravity (9.8 m/s²). \[ F_g = 120 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 1176 \, \text{N} \] 2. **Establish Equilibrium Conditions:** - For horizontal components: \(\sum F_x = T1 \cos(\alpha) - T2 \cos(\beta) = 0\) - For vertical components: \(\sum F_y = T
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Free body diagram
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON