A bag of cement weighing 525 N hangs in equilibrium from three wires as suggested in the figure below. Two of the wires make angles 0₁ = 62.0° and 0₂ = 43.0° with the horizontal. Assuming the system is in equilibrium, find the tensions T₁, T₂, and T3 in the wires. 0 X Consider the net force at the point where the three wires come together. What is the acceleration of this point? N 0.53 X T2 = The horizontal component of your T₁ is not equal to the horizontal component of your T2, so the object would be accelerating horizontally. N T3 = = 525 N T₁ = T₁ T3 0₂ T₂

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Chapter13: Gravitation
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A bag of cement weighing 525 N hangs in equilibrium from three wires as suggested in the figure below. Two of the wires make
62.0⁰ and 02 = 43.0° with the horizontal. Assuming the system is in equilibrium, find the tensions T₁, T2, and T3
angles 0₁
1'
in the wires.
T₁
=
0
=
Consider the net force at the point where the three wires come together. What is the acceleration of this point? N
0.53
X
T₂ = The horizontal component of your T₁ is not equal to the horizontal component of your T₂, so the object would be
accelerating horizontally. N
T3 = 525
N
201
T₁
CEMENT
T3
0₂
T₂
Fg
Transcribed Image Text:A bag of cement weighing 525 N hangs in equilibrium from three wires as suggested in the figure below. Two of the wires make 62.0⁰ and 02 = 43.0° with the horizontal. Assuming the system is in equilibrium, find the tensions T₁, T2, and T3 angles 0₁ 1' in the wires. T₁ = 0 = Consider the net force at the point where the three wires come together. What is the acceleration of this point? N 0.53 X T₂ = The horizontal component of your T₁ is not equal to the horizontal component of your T₂, so the object would be accelerating horizontally. N T3 = 525 N 201 T₁ CEMENT T3 0₂ T₂ Fg
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