A 60 kg person walking at 1 m/sec (~2mph) bumps into a wall and stops in adistance of 2.5cm in about 0.05 sec. what is the force developed on impact?A(mv) = (60 kg ) (1 m/sec) - (60 kg) (0 m/sec) = (60 kg.m/sec)%3D

. The resultant force applied is equal to the rate of change of momentum and it is given by the…

Answered: A 60 kg person walking at 1 m/sec…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A 60 kg person walking at 1 m/sec (~2mph) bumps into a wall and stops in a distance of 2.5cm in about 0.05 sec. what is the force developed on impact? A(mv) = (60 kg ) (1 m/sec) - (60 kg) (0 m/sec) = (60 kg.m/sec) %3D