Answered: A 6-pole synchronous motor has an…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

A 6-pole synchronous motor has an armature impedance of 10 and a resistance of 0.5 ohm. When running on 2.000 volts, 25-Hz supply mains, its field excitation is such that the e.m.f. induced in the machine is 1600 V. Calculate the maximum total torque in N-m developed before the machine drops out of synchronism.

Expert Solution

Step 1

We have an 6-pole synchronous motor having,

Armature impedance (Z_s) = 10 Ω

Resistance (R_a) = 0.5 Ω

Voltage (V) = 2 V

Supply frequency (f) = 25 Hz

Emf in armature (E_b) = 1600 V

we need to determine the maximum total torque in N-m.

For finding the maximum total torque we have,

T_g_(max) = 9.55 * $\frac{m a x i m u m p o w e r}{S y n c h r o n o u s s p e e d}$

So,

First we will need to determine the value of maximum power and synchronous speed.

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