A 6-phase ∆-connected 1600 V (line-to-line), 150 kW, 50 Hz, six-pole induction drive is used in an electric car. The drive has the following parameter values in Ω/phase referred to the stator: R1 =0.334 Ω R2 =0.168 Ω Rm1 = 125 Ω X1 = 0.273 Ω X2 = 0.287 Ω Xm1 = 16.78 Ω The total friction, windage, and core losses may be assumed to be constant at Prot = 773 W, independent of load. For a slip value of s=0.015: b ) Compute the speed, output torque, power and stator current d) Calculate the efficiency when the motor is operated at rated voltage and frequency. answer:b) n= 985 rpm; Torque T= 1.18 x104 Nm; Power= 1.22 x106 W; Stator current I = 175.72 /32.79° (d) Efficiency = 86.4%
A 6-phase ∆-connected 1600 V (line-to-line), 150 kW, 50 Hz, six-pole induction drive is used in an electric car. The drive has the following parameter values in Ω/phase referred to the stator: R1 =0.334 Ω R2 =0.168 Ω Rm1 = 125 Ω X1 = 0.273 Ω X2 = 0.287 Ω Xm1 = 16.78 Ω The total friction, windage, and core losses may be assumed to be constant at Prot = 773 W, independent of load. For a slip value of s=0.015: b ) Compute the speed, output torque, power and stator current d) Calculate the efficiency when the motor is operated at rated voltage and frequency. answer:b) n= 985 rpm; Torque T= 1.18 x104 Nm; Power= 1.22 x106 W; Stator current I = 175.72 /32.79° (d) Efficiency = 86.4%
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Question
A 6-phase ∆-connected 1600 V (line-to-line), 150 kW, 50 Hz, six-pole induction drive
is used in an electric car. The drive has the following parameter values in Ω/phase
referred to the stator:
R1 =0.334 Ω R2 =0.168 Ω Rm1 = 125 Ω
X1 = 0.273 Ω X2 = 0.287 Ω Xm1 = 16.78 Ω
The total friction, windage, and core losses may be assumed to be constant at Prot =
773 W, independent of load. For a slip value of s=0.015:
b ) Compute the speed, output torque, power and stator current
d) Calculate the efficiency when the motor is operated at rated voltage and
frequency.
answer:b) n= 985 rpm; Torque T= 1.18 x104 Nm; Power= 1.22 x106 W; Stator current I = 175.72 /32.79°
(d) Efficiency = 86.4%
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