A 300 V, 2 pole, 60 Hz Y connected wound rotor induction motor is rated 25 Hp. Its equivalents circuit components are R, = 0.3 Q R = 0.13 Q Хи 3 16.0 X, = 0.5 Q X2 = 0.5 Q Pmech = 250 WPmise = 0 Pcore = 150 W For a slip of 0.06, find 1. The line current I. 2. The stator copper losses PscL 3. The air gap power PAG 4. The power converted from electrical to mechanical form Ponv 5. The induced torgue Tnd

A 300 V, 2 pole, 60 Hz Y connected wound rotor induction motor is rated 25 Hp. Its equivalents circuit components are R, = 0.3 Q R = 0.13 Q Хи 3 16.0 X, = 0.5 Q X2 = 0.5 Q Pmech = 250 WPmise = 0 Pcore = 150 W For a slip of 0.06, find 1. The line current I. 2. The stator copper losses PscL 3. The air gap power PAG 4. The power converted from electrical to mechanical form Ponv 5. The induced torgue Tnd

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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