A 47.00 ml aliquot from a 0.490 L solution that contains 0.410 g of MnSO, (MW = 151.00 g/mol) required 40.7 mL of an EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCO, ( MW = 100.09 g/mol) will react with 1.61 ml. of the EDTA solution? mass: mg

A 47.00 ml aliquot from a 0.490 L solution that contains 0.410 g of MnSO, (MW = 151.00 g/mol) required 40.7 mL of an EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCO, ( MW = 100.09 g/mol) will react with 1.61 ml. of the EDTA solution? mass: mg

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A 47.00 ml aliquot from a 0.490 L solution that contains 0.410 g of MnSO, (MW = 151.00 g/mol) required 40.7 mL of an
EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCO, ( MW = 100.09 g/mol) will react
with 1.61 ml. of the EDTA solution?
mass:
mg

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