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A 250.0-mL sample of 0.125 M N.3PO, is mixed with 250.0 mL of 0.175 M Ca(NO,), to form Ca3(PO4)2. The net ionic equation for the reaction is given below: 3 Ca2+ 3 Ca (aq) + 2 PO, (aq) Ca3(PO4)2(s) What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are additive?

A 250.0-mL sample of 0.125 M N.3PO, is mixed with 250.0 mL of 0.175 M Ca(NO,), to form Ca3(PO4)2. The net ionic equation for the reaction is given below: 3 Ca2+ 3 Ca (aq) + 2 PO, (aq) Ca3(PO4)2(s) What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are additive?

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter3: Mass Relations In Chemistry; Stoichiometry
Section: Chapter Questions
Problem 24QAP: Twenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What is the...
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A 250.0-mL sample of 0.125 M NagPO, is mixed with 250.0 mL of 0.175 M Ca(NO3)2 to form Ca3(PO4)2. The net ionic equation for the reaction is given below: 3 Ca" (aq) + 2 PO4 (aq) + Ca3(PO,)2(s) 3- What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are additive?
Transcribed Image Text:A 250.0-mL sample of 0.125 M NagPO, is mixed with 250.0 mL of 0.175 M Ca(NO3)2 to form Ca3(PO4)2. The net ionic equation for the reaction is given below: 3 Ca" (aq) + 2 PO4 (aq) + Ca3(PO,)2(s) 3- What is the concentration of the excess reactant ion in the resulting solution assuming that the volumes are additive?
Select one: O a. 2.5 x 10-2 M Ca2+ O b. 9.38 x 10-3 M Ca2+ 5.83 x 10-2 M PO,3- C. O d. 4.17 x 10-3 M PO43- Clear my choice
Transcribed Image Text:Select one: O a. 2.5 x 10-2 M Ca2+ O b. 9.38 x 10-3 M Ca2+ 5.83 x 10-2 M PO,3- C. O d. 4.17 x 10-3 M PO43- Clear my choice
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