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A 15.0 V power supply is connected across two parallel plates which are separated by a distance of d= 7.0 cm. An electron is launched horizontally at a speed of 4.40×10“ m/s exactly halfway between the plates (a distance of 3.5 cm from either plate). Part A Calculate the electric field strength. E = N/C or V /m Submit Request Answer Part B Calculate the time (after entering the parallel plate capacitor) when the electron will collide with the positive plate. (Ignore the effects of gravity) t = Part C Calculate the location (horizontal distance) where the electron will collide with the positive plate. m

A 15.0 V power supply is connected across two parallel plates which are separated by a distance of d= 7.0 cm. An electron is launched horizontally at a speed of 4.40×10“ m/s exactly halfway between the plates (a distance of 3.5 cm from either plate). Part A Calculate the electric field strength. E = N/C or V /m Submit Request Answer Part B Calculate the time (after entering the parallel plate capacitor) when the electron will collide with the positive plate. (Ignore the effects of gravity) t = Part C Calculate the location (horizontal distance) where the electron will collide with the positive plate. m

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A 15.0 V power supply is connected across two parallel plates which are separated by a distance of d = 7.0 cm. An electron is launched horizontally at a speed of 4.40x104 m/s exactly halfway between the plates (a distance of 3.5 cm from either plate). +) +, Part A Calculate the electric field strength. Πνα ΑΣφ E = N/C or V/m Submit Request Answer Part B Calculate the time (after entering the parallel plate capacitor) when the electron will collide with the positive plate. (Ignore the effects of gravity) VO AZ t= Part C Calculate the location (horizontal distance) where the electron will collide with the positive plate. nνα ΑΣφ ? d = m Submit Request Answen
Transcribed Image Text:A 15.0 V power supply is connected across two parallel plates which are separated by a distance of d = 7.0 cm. An electron is launched horizontally at a speed of 4.40x104 m/s exactly halfway between the plates (a distance of 3.5 cm from either plate). +) +, Part A Calculate the electric field strength. Πνα ΑΣφ E = N/C or V/m Submit Request Answer Part B Calculate the time (after entering the parallel plate capacitor) when the electron will collide with the positive plate. (Ignore the effects of gravity) VO AZ t= Part C Calculate the location (horizontal distance) where the electron will collide with the positive plate. nνα ΑΣφ ? d = m Submit Request Answen
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