A 15.0 V power supply is connected across two parallel plates which are separated by a distance of d = 7.0 cm. An electron is launched horizontally at a speed of 4.40x104 m/s exactly halfway between the plates (a distance of 3.5 cm from either plate).+)+,Part ACalculate the electric field strength.Πνα ΑΣφE =N/C or V/mSubmitRequest AnswerPart BCalculate the time (after entering the parallel plate capacitor) when the electron will collide with the positive plate. (Ignore the effects of gravity)VO AZt=Part CCalculate the location (horizontal distance) where the electron will collide with the positive plate.nνα ΑΣφ?d =mSubmitRequest Answen

Power supply Vo = 15.0 V distance between plates d = 7.0 cm = 0.07 m Electron speed v = 4.40 × 104…

Answered: A 15.0 V power supply is connected…

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