n electron is fired in the positive y-direction from x= -3.00 cm in a constant electric field with magnitude 1.88 x 103N/C pointing in the positive y-direction. The moment the electron is at the position x = 2.00 cm 1. how far has the electron travelled in meters? 2. The electron has __________ electric potential energy at the new position. 3. Calculate the magnitude of the potential energy at the new position. The charge of an electron is 1.60 x 10-19 C. 4. Determine the initial velocity of the electron given that its speed is two-third of its initial velocity when it reaches its new position. The mass of an electron is 9.11 x 10-31 kg.

n electron is fired in the positive y-direction from x= -3.00 cm in a constant electric field with magnitude 1.88 x 103N/C pointing in the positive y-direction. The moment the electron is at the position x = 2.00 cm 1. how far has the electron travelled in meters? 2. The electron has __________ electric potential energy at the new position. 3. Calculate the magnitude of the potential energy at the new position. The charge of an electron is 1.60 x 10-19 C. 4. Determine the initial velocity of the electron given that its speed is two-third of its initial velocity when it reaches its new position. The mass of an electron is 9.11 x 10-31 kg.

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Question

An electron is fired in the positive y-direction from x= -3.00 cm in a constant electric field with magnitude 1.88 x 10³N/C pointing in the positive y-direction. The moment the electron is at the position x = 2.00 cm

1. how far has the electron travelled in meters?

2. The electron has __________ electric potential energy at the new position.

3. Calculate the magnitude of the potential energy at the new position. The charge of an electron is 1.60 x 10^-19 C.

4. Determine the initial velocity of the electron given that its speed is two-third of its initial velocity when it reaches its new position. The mass of an electron is 9.11 x 10^-31 kg.

Expert Solution

Step 1

Given:

X=-3 cm

E=1.88 $\times$ 10³ N/C

X=2 cm

Step 2

Formula used:

$KE = \frac{1}{2} m ({v_{f}}^{2} {v_{i}}^{2})$

v_i=initial velocity

v_f=final velocity

m=mass

Step by step

Solved in 4 steps

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